Observer A is moving inside the train
so here observer A will not be able to see the change in position of train as he is standing in the same reference frame
So here as per observer A the train will remain at rest and its not moving at all
Observer B is standing on the platform so here it is a stationary reference frame which is outside the moving body
So here observer B will see the actual motion of train which is moving in forward direction away from the platform
Observer C is inside other train which is moving in opposite direction on parallel track. So as per observer C the train is coming nearer to him at faster speed then the actual speed because they are moving in opposite direction
So the distance between them will decrease at faster rate
Now as per Newton's II law
F = ma
Now if train apply the brakes the net force on it will be opposite to its motion
So we can say
- F = ma

so here acceleration negative will show that train will get slower and its distance with respect to us is now increasing with less rate
It is not affected by the gravity because the gravity will cause the weight of train and this weight is always counterbalanced by normal force on the train
So there is no effect on train motion
Answer: 0.4 m
Explanation:
Given
Speed of ambulance, vs = 61.9 m/s
Speed of car = 28.5 m/s
Frequency of ambulance siren, f = 694 Hz
Velocity of sound in air, v = 343 m/s
With speed of ambulance being (61.9 m/s) -> We solve using
fd = f(v + vr) / (v - vs), where vr = 0
fd = 694 * (343 + 0) / (343 - 61.9)
fd = 694 * (343 / 281.1)
fd = 694 * 1.22
fd = 847 Hz
Recall,
λ = v/f
λ = 343/847
λ = 0.4 m
Therefore, the wavelength of the sound of the ambulance’s siren if you are standing at the position of the car is 0.4 m
They are unproven but accepted as fact.
Many experiments support them but they can be disproven by the results of a single experiment. Until then, they stand.
The third statement is correct.
Use this numbers that you are given and plug them into the formule for net force
Net force= m*a (mass times acceleration)
Therefore the net force is equal to (5.5 kg)*(4.2 m/s^2)= 23.1 N
Answer: Net force= 23.1 N
Answer:
40.91 m/s
Explanation:
w = angular velocity of the ball about the elbow joint = 30.3 rad/s
r = radius of circular turn = distance of the ball from the elbow joint = 1.35 m
v = linear velocity of the ball
Linear velocity of the ball is given as
v = r w
Inserting the values given above in the equation
v = (1.35) (30.3)
v = 40.91 m/s