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Aliun [14]
3 years ago
6

In lacrosse, a ball is thrown from a net on the end of a stick by rotating the stick and forearm about the elbow. If the angular

velocity of the ball about the elbow joint is 30.3 rad/s30.3 rad/s and the ball is 1.35 m1.35 m from the elbow joint, what is the velocity ????v of the ball?
Physics
1 answer:
Darya [45]3 years ago
7 0

Answer:

40.91 m/s

Explanation:

w = angular velocity of the ball about the elbow joint = 30.3 rad/s

r = radius of circular turn = distance of the ball from the elbow joint = 1.35 m

v = linear velocity of the ball

Linear velocity of the ball is given as

v = r w

Inserting the values given above in the equation

v = (1.35) (30.3)

v = 40.91 m/s

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Explanation:

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Substituting the values in the equation

(.3189 x 24 x 60 x 60 s)²  = 4 x 3.14² x ( 9380 x 10³)³ / (6.67 x 10⁻¹¹ x M)

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Jupiter's moon Io has active volcanoes (in fact, it is the most volcanically active body in the solar system) that eject materia
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Answer:

The height reached by the material on Earth is 91 km.

Explanation:

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Mass M_{Io}=8.93\times10^{22}\ kg

Radius = 1821 km

Height h_{Io}=500\ km

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We need to calculate the acceleration due to gravity on Io

Using formula of gravity

g =\dfrac{GM_{Io}}{(R_{Io})^2}

Put the value into the formula

g=\dfrac{6.67\times10^{-11}\times8.93\times10^{22}}{(1821\times10^{3})^2}

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Let  v be the speed at which the material is ejected.

We need to calculate the height

Using the formula of height

H=\dfrac{v^2}{2g}

Using ratio of height of earth and height of Io

\dfrac{H_{e}}{H_{Io}}=\dfrac{\dfrac{v^2}{2g_{e}}}{\dfrac{v^2}{2g_{Io}}}

\dfrac{H_{e}}{H_{Io}}=\dfrac{g_{Io}}{g_{e}}

Put the value into the formula

\dfrac{H_{e}}{H_{Io}}=\dfrac{1.79}{9.8}

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H_{e}=91\ km

Hence, The height reached by the material on Earth is 91 km.

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3 years ago
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