Complete Question
At what angle should the axes of two Polaroids be placed so as to reduce the intensity of the incident unpolarized light to 1/5.
Answer:
The angle is
Explanation:
From the question we are told that
The light emerging from second Polaroid is 1/5 the unpolarized
Generally the intensity of light emerging from the first Polaroid is mathematically represented as

Generally from the Malus law the intensity of light emerging from the second Polaroid is mathematically represented

=> 
=> 
From the question


=> ![\theta = cos ^{-1} [\sqrt{\frac{2}{5}} ]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%20%20cos%20%5E%7B-1%7D%20%5B%5Csqrt%7B%5Cfrac%7B2%7D%7B5%7D%7D%20%20%5D)
=> 
Answer:
The net torque is 0.4962 N m
Explanation:
please look at the solution in the attached Word file
Shortwave radios have a higher frequency than ultraviolet light
Answer:500hz
Explanation:
Frequency=velocity/wavelength
Frequency=1500/3
Frequency=500hz
Not sure what the given options are, but the answer is the horizontal component. This is given by Force x cos(angle), or Fcos(θ), where θ is the angle. In this case that would be 20cos(30) = 17.32N