Question must be solved using only symbolic algebra.During the experiment if you could triple the breakaway magnetic force with
all other quantities left unchanged, what is the new value for the critical velocity if it was v0 (initial velocity), initially? (b) Now if you halved the radius with all other quantities left unchanged, what is the new critical velocity if it was v0 (initial velocity), initially? (c) If during the experiment, critical velocity quadrupled with all other quantities left unchanged, what is the new breakaway force if its magnitude was initially F0,?
1 answer:
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Answer:
a) M = 2,939 10¹⁷ kg
, b) / M = 2 10⁷
Explanation:
a) The equation for gravitational force is
F = G m M / r²
Where G is the gravitational constant that is worth 6.67 10⁻¹¹ N m² / kg², m the mass epa person. M the mass of the Mountain and r the distance between them.
The value of this force is 2% of the person's weight
F = 0.02 W = 0.02 mg
we replace
0.02 mg = G m M / r²
M = 0.02 g r² / G
r = 10 km = 10 10³ m = 1.0 10⁴ m
M = 0.02 9.8 (10⁴)² / 6.67 10⁻¹¹
M = 2,939 10¹⁷ kg
b) to compare the masses we find their relationship
/ M = 5.98 1024 / 2,939 1017
/ M = 2 10⁷
c) treating the mountain as a point object
d) The mountain is not spherical so the distance changes depending on the height of the mountain