The resistance of the sample is 
Explanation:
The relationship between resistance of a material and temperature is given by the equation

where
is the resistance at the temperature 
is the temperature coefficient of resistance
For the sample of nickel in this problem, we have:
when the temperature is 
While the temperature coefficient of resistance of nickel is

Therefore, the resistance of the sample when its temperature is

is

Learn more about resistance:
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Mass.
Because mass doesn't depend on weight but weight depends on mass.
The correct answer is “C” ultrasound. Hope this helps!
Answer:
0.74 N/cm
Explanation:
The following data were obtained from the question:
Mass (m) = 3 Kg
Extention (e) = 40 cm
Spring constant (K) =?
Next, we shall determine the force exerted on the spring.
This can be obtained as follow:
Mass (m) = 3 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Force (F) =?
F = mg
F = 3 × 9.8
F = 29.4 N
Finally, we shall determine the spring constant of the spring. This can be obtained as follow:
Extention (e) = 40 cm
Force (F) = 29.4 N
Spring constant (K) =?
F = Ke
29.4 = K × 40
Divide both side by 40
K = 29.4 / 40
K = 0.74 N/cm
Therefore, the spring constant of the spring is 0.74 N/cm