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3 years ago

An object with a mass of m = 3.00 kg has an initial velocity of vi = 6.00 m/s and a final velocity of vf = −8 m/s.

Physics

1 answer:

Triss [41]3 years ago

7 0

Answer:

The answer to your question is below

Explanation:

Data

m = 3 kg

vo = 6 m/s

vf = -8 m/s

Process

a= Initial kinetic energy

Eko = (1/2)mv²

Eko = (1/2)(3)(6)²

Eko = 54 J

b) Final kinetic energy

Eko = (1/2)(3)(-8)²

Eko = 96 J

c) Initial momentum

pi = (3)(6)

pi = 18 kg m/s

d) Final momentum

pf = (3)(-8)

pf = -24 kg m/s

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jeyben [28]

Answer:

16 times

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2 years ago

A particle with charge q = 10-9 C and mass m = 5.0 x 10-9 kg is moving in a magnetic field whose magnitude is 0.003 T. The speed

Marina86 [1]

Answer:

a=0.212 m/s²

Explanation:

Given that

q= 10⁻⁹ C

m = 5 x 10⁻⁹ kg

Magnetic filed ,B= 0.003 T

Speed ,V= 500 m/s

θ= 45°

Lets take acceleration of the mass is a m/s²

The force on the charge due to magnetic filed B

F= q V B sinθ

Also F= m a ( from Newton's law)

By balancing these above two forces

m a= q V B sinθ

$a=\dfrac{qVB\ sin\theta}{m}$

$a=\dfrac{10^{-9}\times 500\times 0.003\times\ sin45^{\circ}}{5\times 10^{-9}}\ m/s^2$

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3 years ago