Question

A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235 m below. If the plane is traveling horizontally with a speed of 250 km/hr (69.4 m/s) how far in advance of the recipients (horizontal distance) must the goods be dropped

Answer 1

Answer:

481 m

Explanation:

To fall 235 m, the time required is

t = √(2H/g)

t= √(2$\times$235/9.8)

t=6.92 seconds.

The supplies will travel forward

6.92 $\times$ 69.4 ≈ 481 m

Therefore, the goods must be dropped 481  m in advance of the recipients.