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3 years ago

Determine the next two numbers in the sequence (4, 7, 10, 13, x, x)

Mathematics

2 answers:

Aneli [31]3 years ago

8 0

Answer:

The answer would be (4, 7, 10, 13, 16, 19)

Step-by-step explanation:

4+3=7

7+3=10

The equation would be X+3 so add 3 to each number and you should have your answer, I hope this helped!!!

arlik [135]3 years ago

7 0

Answer:

16,19

Step-by-step explanation:

If we look closely, we can see that each number is 3 more than the last number.

4+3=7

7+3=10

10+3=13

13+3= 16

16+3=19

Hope this helps!

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Which equation represents "the sum of eight times a number and seven is twice the number"? A) 8(7 + 2N) B) 8N = 7 + 2N. C) 7N +

Yuliya22 [10]

The sum of 8 times a number and 7.....sum means add
8n + 7

is twice the number...is means equals
= 2n

so we have : 8n + 7 = 2n

7 0

3 years ago

Read 2 more answers

Which of the following has factor of (× - 4) (× - 3)?

julia-pushkina [17]

Answer:

Hello!

After reading your question I have come up with the correct way to factor (x-4) and (x-3) together:

x²-7x+12

Step-by-step explanation:

This is my work:

3 0

2 years ago

Plz help i need it!!

Umnica [9.8K]

Answer: c) 19,807

<u>Step-by-step explanation:</u>

$A=A_o\cdot e^{kt}\\\\\bullet A_o\text{ is the initial population}\\\bullet \text{k is the rate of decrease}\\\bullet \text{t is the number of years after 2010}\\\\A=22,000\cdot e{(-0.021)(5)}\\.\ =22,000\cdot e^{-0.105}\\.\ =19,807$

6 0

2 years ago

u can look this up here on brainly for an answer source if you want but do the one that has the greatest points... its on google

Alla [95]

Answer:

First one is 41

Second one is 87

Step-by-step explanation:

Make the shaded part as a trapezoid which is (3+6)*10/2 you just have to get rid of 2*2. So you get 41 as the answer.

The unshaded part will be 16*8 then subtracts the shaded part which is 41. Then you get the answer 87.

6 0

3 years ago

2/3*5/15+-24+-18 pls help asap

zavuch27 [327]

Answer:

-42 2/9

Step-by-step explanation:

⭐ Please consider brainliest! ⭐

✉️ If any further questions, inbox me! ✉️

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3 years ago