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harina [27]
3 years ago
13

A Cassegrain telescope

Physics
1 answer:
yuradex [85]3 years ago
3 0

The answer is D.

Hope this helps and have a good day :D

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A 12 kg box is pulled across the floor with a 48 N horizontal force. If the force of friction is 12 N, what is the acceleration
Oksi-84 [34.3K]

Answer:

The acceleration of the box is 3 m/s²

Explanation:

Given;

mass of the box, m = 12 kg

horizontal force pulling the box forward, Fx = 48 N

frictional force acting against the box in opposite direction, Fk = 12 N

The net horizontal force on the box, F = 48 N - 12 N

The net horizontal force on the box, F = 36 N

Apply Newton's second law of motion to determine the acceleration of the box;

F = ma

where;

F is the net horizontal force on the box

a is the acceleration of the box

a = F / m

a = 36 / 12

a = 3 m/s²

Therefore, the acceleration of the box is 3 m/s²

7 0
3 years ago
A block of mass 8 m can move without friction
nekit [7.7K]

Answer:

Let M1 = 8 kg and M2 = 34 kg

F = M a = (M1 + M2) a

F = M2 g     the net force accelerating the system

M2 g = (M1 + M2) a

a = M2 / (M1 + M2) g = 34 / (42) g = .81 g = 7.9 m/s^2

5 0
2 years ago
Thank you so muchhhhh
padilas [110]

Answer:

c. the rotation and revolution of the moon are the same as the earth

Explanation:

that we only see one side of the moon because the moon rotates around the Earth at the exact same speed as it rotates around its own axis, so that the same side of the moon is constantly facing the surface of the earth.

6 0
3 years ago
Read 2 more answers
You grab a car door handle in the summer (energy transfer to heat up the handle ____) and it burns you through energy transfer.
Cerrena [4.2K]

Answer: conduction

Explanation:

Because you are physically touching the handle

6 0
3 years ago
.A 0.2-kg aluminum plate, initially at 20°C, slides down a 15-m-long surface, inclined at a 30 angle to the horizontal. The forc
Ainat [17]

To solve this problem, it is necessary to apply the concepts related to Work according to the Force and distance, as well as the concepts related to energy lost-or gained-by heat. Mathematically the energy corresponding to heat is given as:

Q = mC_p(\Delta T)

Where,

m = mass

C_p= Specific heat

\Delta T = Change in Temperature

At the same time the Work made by the Force and the distance is given as:

W = F*d \rightarrow W=mg*d

As the force is applied at an angle of 30 degrees, the efficient component would be given by the vertical then the work / energy would be determined as:

W = mg*dsin(30)

W = (15m)(0.2kg)(9.81)(sin30)

W = 13.24J

Now this energy is used to heat the aluminum. We can find the change at the temperature as follow:

Q = mC_p(\Delta T)

13.24 = (0.2)(900)(\Delta T)

\Delta T = 0.0736 \°C

Therefore the correct answer is B.

7 0
3 years ago
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