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shutvik [7]
2 years ago
5

The equation of trajectory of a projectile is y=10x-(5/9)x^2 if we assume g=10m/s^2, the range of projectile in meters is?

Physics
1 answer:
Morgarella [4.7K]2 years ago
5 0

Answer:

18 m

Explanation:

y = 10x − 5/9 x²

When the projectile lands, y=0:

0 = 10x − 5/9 x²

0 = x (10 − 5/9 x)

x = 0, 18

The range of the projectile is 18 m.

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