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Hitman42 [59]
3 years ago
8

Answer the following question: “Do the particles in a gas ever slow down and stop? Include information about the three states of

matter”

Physics
1 answer:
jarptica [38.1K]3 years ago
3 0

Answer:

I hope it is no too late

Explanation:

hmmm,

In a gas, for example, the molecules are traveling in random directions at a variety of speeds - some are fast and some are slow. ... If more energy is put into the system, the average speed of the molecules will increase and more thermal energy or heat will be produced.

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How many atoms of Oxygen (O) are in 3CO2
ikadub [295]

Answer:

2

Explanation:

BRAINLIEST?? AND THANK ME LATER!!! HOPE THIS HELPED!!!

5 0
3 years ago
A comet is first seen at a distance of d astronomical units from the Sun and it is traveling with a speed of q times the Earth’s
saw5 [17]

To solve this problem it is necessary to take into account the concepts of Gravitational Force and Kinetic Energy.

The kinetic energy is given by the equation:

F= \frac{mv^2}2

La energía gravitacional por,

F=\frac{GM_cm}{d}

Where m is the mass, v is the velocity, G the gravitational constant M_e the mass of the earth, m the mass of the sun and d the distance ..

The sum of the energies, we must be a total energy

E= \frac{mv^2}2+\frac{GM_em}{d}

By the type of orbit we know that

E> 0 is a hyperbolic orbit

E = 0 is a parabolic orbit

E <0 is a closed orbit.

In the case of hyperbolic orbit

E>0

\frac{mq^2}{2}-\frac{GM_em}{d}>0\\\frac{qv^2_e}{2}>\frac{GM_em}{d}\\q^2d>2\frac{GM_e}{v^2_e}\\q^2d>2

The case of the comet is a closed orbit, so,

E<0

\frac{mv^2}2+\frac{GM_em}{d}

For parabolic orbit

E=0

\frac{mv^2_eq^2}{2}-\frac{GM_cm}{d}=0\\\frac{v^2_eq^2}{2}=\frac{GM_c}{d}\\q^2d=2\frac{GM_e}{v^2_e}\\q^2d=2

For the sun and the earth

\frac{m_ev_e^2}{r}=\frac{GM_em_e}{r^2}

v^2_e=\frac{GM_e}{r}\\\frac{GM_e}{v_e}=r

where R \approx 1AU

q^2d  For elliptical orbit

8 0
3 years ago
Plsss help jdybgdykhbskyhdigbjs
Marta_Voda [28]
<h2>ANSWER: </h2><h2>_____________________________________</h2><h2>TYPES OF CHEMICAL REACTIONS:</h2>

There are two types of Reactions,

<h3>Endothermic Reactions: </h3>

Endothermic reactions are the type chemical reaction in which the reactants absorb heat energy from the surroundings. The energy of reactants is more than the energy of product

<h3>Exothermic Reactions: </h3>

Exothermic reactions are the type of chemical reactions in which release of energy takes place in the form of heat or light. In an exothermic reaction, energy is released. The energy of the products is less than the energy of the reactants.

<h2>_____________________________________</h2><h3 /><h3>In Question number 5,</h3>

The key word is "RELEASE". The reaction in which energy is released is the Exothermic reaction thus the Option B that is EXOTHERMIC REACTION is correct.

<h2>_____________________________________</h2><h3 /><h3>In Question number 6</h3>

It is asking that which process stores the energy that means it is asking which process undergoes endothermic reaction. The answer is Option C that is PHOTOSYNTHESIS is correct.

<h3>__________________________________________________</h3><h3>WHY PHOTOSYNTHESIS?</h3>

Because, sunlight is being absorbed during the reaction and according to the definition of endothermic reaction if heat is being absorbed it is termed as an endothermic reaction.

<h3>__________________________________________________</h3><h3 /><h3 />
7 0
3 years ago
Read 2 more answers
An airplane is flying from Dallas, Texas to Pensacola, Florida. Flying at maximum velocity, it encounters strong winds moving at
jenyasd209 [6]

Answer:

G. It will take twice as long.

Explanation:

Let's call v the original speed of the plane and d the distance between Dallas and Pensacola. The time the plane originally takes to complete the flight is

t=\frac{d}{v}

In this problem, we are told that the plane encounters wind moving at half of its speed: \frac{v}{2}, in the opposite direction. This means that the new speed of the plane is

v'=v-\frac{v}{2}=\frac{v}{2}

And so, the time the plane takes now to complete the flight is

t'=\frac{d}{v/2}=2\frac{d}{v}=2t

So, the plane takes twice the time as before.

4 0
3 years ago
A boy throws a ball vertically up. It returns to the
NikAS [45]

Answer:

31.25 m

25m/sec

Explanation:

Given :-

Time = 5sec

V = 0 (in going up)

U = 0 (in comming down)

Find :-

H and U by which it is thrown up

Since the total time is 5 sec ,therefore half time will be taken to go up and another half will be taken to go down .

We know that ,

V = U + gt

0 = U - 10*2.5

U = 25 m/sec

Also,

V² = U² +2gs

0 = 625 - 20s

s = 625/20 = 31.25 m

7 0
3 years ago
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