Answer:
a) 
b) 
c) 
Explanation:
Before the wire is inserted, the total charge on the inner and outer surface of the cylindrical shell is as follows:
Here, 'h' denotes the length of the cylinder. The total charge of the cylindrical shell is -0.395h μC.
When the thin wire is inserted, the positive charge of the wire attracts the same amount of negative charge on the inner surface of the shell.
a) The new charge on the inner shell is -1.1h μC. Therefore, the new surface charge density of the inner shell can be calculated as follows:
b) The new charge on the outer shell is equal to the total charge minus the inner charge. Therefore, the new charge on the outer shell is +0.705 μC.
The new surface charge density can be calculated as follows:
c) The electric field outside the cylinder can be found by Gauss' Law:
We will draw an imaginary cylindrical shell with radius r > r2. The integral in the left-hand side will be equal to the area of the imaginary surface multiplied by the E-field.
<span>The answer is a. cutting trees reduce fertility and eliminates animal habitats. Plant material is essential in maintaing soil fertility. Leaves and branches decay to form humus; removing trees decreases the organic content. Trees are home to many animal species, including birds, insects and amphibians. Some trees are even support or home to other plants. Examples include epiphytes in the rainforest ecosystem. Clear cutting forests disrupts whole communities and ecosystems. </span>
The calorie was originally defined as the amount of heat required at a pressure of 1 standard atmosphere to raise the temperature of 1 gram of water 1° Celsius. ... Since 1925 this calorie has been defined in terms of the joule, the definition since 1948 being that one calorie is equal to approximately 4.2 joules.
Answer:
a) K_e = 0.1225 J, b) U = 1.96 J, c) v = 0.99 m / s
Explanation:
Let's use the simple harmonium movement expression
y = A cos (wt + Ф)
indicate that the amplitude is
A = 0.05 m
as the system is released, the velocity at the initial point is zero
v = dy / dt
v = - A w sin (wt + Ф)
for t = 0 s and v = 0 m/s
0 = - A w sin Ф
so Ф = 0
the expression of the movement is
y = 0.05 cos wt
The total energy of the system is
Em = ½ k A²
let's use conservation of energy
starting point. Spring if we stretch and we set the zero of our system at this point
Em₀ = K_e + U
Em₀ = 0
final point. When weight and elastic force are in balance
Em_f = K_e + U
Em_f = ½ k y² + m g (-y)
energy is conserved
Em₀ = Em_f
0 = ½ k y² + m g (-y)
k = 2mg / y
k = 2 4.00 9.8 / 0.050
k = 98 N / m
a) maximum elastic energy
K_e = ½ k A²
K_e = ½ 98 0.05²
K_e = 0.1225 J
b) the maximum gravitational energy
U = m g y
U = 4.00 9.8 0.05
U = 1.96 J
c) The maximum kinetic energy occurs when the spring is not stretched
U = K
mg h = ½ m v²
v = √2gh
v = √( 2 9.8 0.05)
v = 0.99 m / s
d) energy at any point
Em = K + U
conduction because energy is being conducted throughout the spoon
