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3 years ago

9

Write the number of permutations in factorial form. Then simplify, how many different ways can you and six of your friends sit i

n your assigned seats in math class
A)6!; 120
B)6!;720
c)7!;2,520
D) 7!;5,040

2 answers:

kari74 [83]3 years ago

6 0

You and 6 of your friends. Total of 7 people.

The answer is D.) 7! ; 5,040

Rainbow [258]3 years ago

6 0

Answer: D) 7!;5,040

Step-by-step explanation:

Given: The number of friends = 7

Permutations says that the number of different ways of arranging r objects out of n objects is given by ;-

$^nP_r=\dfrac{n!}{(n-r)!}$

By permutations the number of different ways they can sit is given by :-

$^7P_7=\dfrac{7!}{(7-7)!}=\dfrac{7!}{0!}\\\\=7\times6\times5\times4times3\times2\times1\\\\=5,040$

Therefore, the different ways can you and six of your friends sit in your assigned seats in math class = 5,040.

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