<span>I note that this problem starts out with "Which is a factor of ... " This implies that you were given several answer choices. If that's the case, it's unfortunate that you haven't shared them.
I thought I'd try finding roots of this function using synthetic division. See below:
f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35
Please use " ^ " to denote exponentiation. Thanks.
Possible zeros of this poly are factors of 35: plus or minus 1, plus or minus 5, plus or minus 7. Use synthetic division; determine whether or not there is a non-zero remainder in each case. If none of these work, form rational divisors from 35 and 6 and try them: 5/6, 7/6, 1/6, etc.
Provided that you have copied down the function
</span>f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35 properly, this approach will eventually turn up 1 or 2 zeros of this poly. Obviously it'd be much easier if you'd check out the possible answers given you with this problem.
By graphing this function, I found that the graph crosses the x-axis at 7/2. There is another root.
Using synth. div. to check whether or not 7/2 is a root:
___________________________
7/2 / 6 -21 -4 24 -35
21 0 -14 35
----------- ------------------------------
6 0 -4 10 0
Because the remainder is zero, 7/2 (or 3.5) is a root of the polynomial. Thus, (x-3.5), or (x-7/2), is a factor.
Answer:
Me!!
Step-by-step explanation:
;D
Answer:
<em>1 and 5 over 24</em>
Step-by-step explanation:
its right trust me because 1+1 is 3
Answer:
its answer b
Step-by-step explanation:
B:(m∠1 + m∠2) = 180° and (m∠3 + m∠4) = 180°
<span>
<span><span>
x
y=2*(0.5)^x
</span><span>-10
2048
</span>
<span>
-9
1024
</span>
<span>
-8
512
</span>
<span>
-7
256
</span>
<span>
-6
128
</span>
<span>
-5
64
</span>
<span>
-4
32
</span>
<span>
-3
16
</span><span>-2
8
</span>
<span>
-1
4
</span>
<span>
0
2
</span>
<span>
1
1
</span>
<span>
2
0.5
</span>
<span>
3
0.25
</span>
<span>
4
0.125
</span>
<span>
5
0.0625
</span>
<span>
6
0.03125
</span>
<span>
7
0.015625
</span>
<span>
8
0.0078125
</span>
<span>
9
0.00390625
</span>
<span>
10
0.00195313
As x goes to negative infinity the function grows to infinity.
As x grows to infinity the function decreases an approximate to zero. </span></span></span>
