Answer:
- 0.25m/s²
Explanation:
Given parameters:
Initial velocity = 40m/s
Final velocity = 30m/s
Time taken = 40s
Unknown:
Acceleration of the car = ?
Solution:
Acceleration is the rate of change of velocity with time.
So;
Acceleration =
Acceleration = = - 0.25m/s²
This implies that the car will decelerate at a rate of 0.25m/s²
Answer:
A)3.8196 * Newtons B) 2.153 *
Newtons
Explanation:
Force = Pressure * Area.
Pressure is given as 120GPa
Area = Cross Sectional Area of Rod = Area Of A circle = π.
Area Expansivity β =
Area Expansivity β = 2α
α = 16.9x10-6/ ° C.
Radius of Rod AB = Half 0f Diameter, 200mm = = 0.1 m
Radius of Rod BC = Half Of Diameter, 150mm = = 0.075 m.
Note: To convert from millimeter to meter you divide by 1000.
Area of Rod AB = π * = 0.0314
Area of Rod BC = π * = 0.0177
.
Change in Area = 2α * Original Area * Temperature Rise. Therefore for
Rod AB = 2 * 16.9* * 0.0314 * 30 = 3.183 *
.
For Rod BC we have = 2 * 16.9* * 0.0177 * 30 = 1.794∈-5
.
The forces on each rods will be given by.
Force AB = Pressure * Area of Rod AB
= 120GPa * 3.183 * gives 3.8196 *
Newtons.
Force BC = Pressure * Area of Rod BC
= 120GPa * 1.794 * gives 2.153 *
Newtons
Answer:
a) 75.5 degree relative to the North in north-west direction
b) 309.84 km/h
Explanation:
a)If the pilot wants to fly due west while there's wind of 80km/h due south. The north-component of the airplane velocity relative to the air must be equal to the wind speed to the south, 80km/h in order to counter balance it
So the pilot should head to the West-North direction at an angle of
relative to the North-bound.
b) As the North component of the airplane velocity cancel out the wind south-bound speed. The speed of the plane over the ground would be the West component of the airplane velocity, which is