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aleksklad [387]

3 years ago

14

The system is immersed in an environment with a constant high temperature T. What would be the energy expectation value of the s

ystem

1 answer:

Svetlanka [38]3 years ago

8 0

Answer:

The energy value is expected to rise steadily until it is equal to a value that depends on the temperature T of the environment.

Explanation:

If a system is immersed into an environment with a constant high temperature, the temperature of the system will also rise until it comes to equilibrium with the temperature of the environment. When this happens, the energy expectation value of the system will now be dependent on the temperature of the environment. This means that the energy of the system will be a function of the temperature of the environment.

This means that

E = f(T)

where E is the energy value of the system

T is the temperature of the environment.

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The flywheel of an engine is rotating at 35.0 rad/s. When the engine is turned off, the flywheel slows at a constant rate and st

castortr0y [4]

Answer:

a. $-1.8rad/s^2$

b. $332.5 rad$

c.52.9 rev

Explanation:

We are given that

Initial angular speed of wheel= $\omega_0=35 rad/s$

Time=t=19 s

Final angular speed= $\omega=0 rad/s$

a.We have to find the angular acceleration of the wheel.

We know that

Angular acceleration $,\alpha=-\frac{\omega_0}{t}$

Using the formula

$\alpha=-\frac{35}{19}=-1.8rad/s^2$

b. $\theta=\frac{1}{2}\omega_0t$

Using the formula

$\theta=\frac{1}{2}(35)\times 19=332.5 rad$

$\theta=332.5 rad$

c. $2\pi$ rad=1 rev

1 rad= $\frac{1}{2\pi}$ rev

332.5 rad= $\frac{332.5}{2\pi}=52.9 rev$

Number of revolutions made by the flywheel in stopping=52.9 rev

4 0

4 years ago

What is does transfusion mean

NikAS [45]

Transfusion: The act of transferring blood from a healthy person, and giving it to another person.

4 0

3 years ago

Starting from rest, an elevator accelerates uniformly between the 1st and 2nd floors, and decelerates uniformly between the 5th

hichkok12 [17]

Answer:

The minimum scale reading during the trip was 560N.

Explanation:

So, in order to solve this problem, we must first prepare a drawing that will represent the situation. (See picture attached)

In the drawing we have the three situations represented. When the elevator goes up, when it travels at a constant velocity and when it decelerates.

We can now do an analysis of each of the situations:

When elevator starts moving:

When the elevator starts moving, it will be accelerated upwards, so the sum of forces will be equal to the mass times the acceleration. In this case, we have two forces, Weight and the normal force, which is the force the floor of the elevator is making upon the scale. This is the reading the scale will give you.

ΣF=ma

-W+N=ma

N=ma+W

As you may see, in this case the weight is added to the force applied by the elevator to accelerate, so the scale reading will be maximum here.

When the elevator has constant velocity:

If the elevator has constant velocity, then its acceleration will be zero, so the sum of the forces will be equal to zero.

ΣF=0

-W+N=0

N=W

On this stage, the scale will return a reading of 800N, since it will not be accelerated.

When the elevator is decelerating:

On the final stage of the trip, the elevator will have a negative acceleration (it is decelerating) so the sum of the forces will be equal to the product between the mass and the acceleration, so we get:

ΣF=-ma

-W+N=-ma

N=W-ma

In this final stage, we can see that the elevator's force is being subtracted from the weight due to the loss of velocity. This is where the scale will give you a minimum reading, so we analyze this stage.

Weight is found by multiplying mass and the acceleration of gravity:

W=mg

so we can rewrite our equation as:

N=mg-ma

when factoring the mass we get:

N=m(g-a)

the mass can be found by dividing the weight into the acceleration of gravity:

W=mg

$m=\frac{W}{g}$

$m=\frac{800N}{10\frac{m}{s^{2}}}$

m=80kg

we know that in the middle of the trip, the elevator will travel 6m in 1s, so the constant velocity is:

$V=\frac{d}{t}$

$V=\frac{6m}{1s}$

$V=6\frac{m}{s}$

this is the initial velocity for the final stage. The acceleration of the final stage can be found with the following formula:

$a=\frac{V_{f}^{2}-V_{0}^{2}}{2x}$

the final velocity is zero since it goes to a stop, so the formula becomes:

$a=\frac{-V_{0}^{2}}{2x}$

when substituting we get:

$a=\frac{-(6m/s)^{2}}{2(6m)}$

$a=-3\frac{m}{s^{2}}$

When substituting values we can now find the scale's reading:

$N=80kg(10m/s^{2}-3m/s^{2})$

$N=80kg(7m/s^{2})$

N=560N

So the minimum scale reading during the trip was 560N

6 0

3 years ago

A vertical piston-cylinder device contains water and is being heated on top of a range. During the process, 63 Btu of heat is tr

jolli1 [7]

Answer:

The water would have a change in the energy of 50 BTU

Explanation:

Under the assumption that the piston-cylinder system is a closed system, then the conservation law of the system would be: $E_{in}-E_{out}=E_{change}$ , where $E_{in}$ is all the energy that goes into the system, $E_{out}$ is all the energy that leaves the system and, $E_{change}$ is the change of the energy of the system.
For this case the energy that is feeded to the system is heat: 63 BTU.
There is two ways that energy is leaving this system: 8 BTU of heat as losses through the side walls and, 5 BTU of work done by the vapor on the piston.
Then the change of energy of the system is: $E_{change}=E_{in}-E_{out}=63 BTU-(8BTU+5BTU)=50BTU$ .

6 0

3 years ago

Which is an example of positive peer pressure?

Firdavs [7]

Answer:

B. A student asking others to join the leadership club.

Explanation:

A parent isn't a peer, therefore can't be peer pressure. Drinking is negative for your body, therefore not positive peer pressure. A teacher isn't a peer, therefore the only answer left is B.

5 0

3 years ago