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PtichkaEL [24]
3 years ago
8

Rewrite this measurement with a simpler unit, if possible. 8.3 kg•m^2/ s^2

Chemistry
1 answer:
Feliz [49]3 years ago
7 0

Answer: 8.3 J

Explanation:

We have the following measurement:

8.3 \frac{kg m^{2}}{s^{2}}

Rearranging the units:

8.3 \frac{kg m}{s^{2}}m

Since 1 Newton is 1 N=1 \frac{kg m}{s^{2}}:

8.3 Nm

Since 1 Joule is 1 J=1 Nm:

8.3 J This is the simplest form possible

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What is the density of an object with a mass of 145.8g and an volume of 91.75 mL?
Over [174]

Answer:

<h2>Density = 1.6 g/mL</h2>

Explanation:

Density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass = 145.8 g

volume = 91.75 mL

Substitute the values into the above formula and solve for the Density

That's

Density =  \frac{145.8}{91.75}

= 1.5891

We have the final answer as

Density = 1.6 g/mL

Hope this helps you

4 0
3 years ago
1) Given 1469 of H₂SO4 how<br> many moles do you have
mart [117]

Answer:

15moles

Explanation:

Given parameters:

Mass of H₂SO₄   = 1469g

Unknown:

Number of moles  = ?

Solution:

To solve this problem, let us first find the molar mass of the given compound;

  molar mass = 2(1) + 32 + 4(16)  = 98g/mol

So;

 Number of moles = \frac{mass}{molar mass}    = \frac{1469}{98}  

 Number of moles  = 15moles

4 0
3 years ago
How many atoms are in a cracker
Juli2301 [7.4K]
Depends how big the cracker is...

It could possibly be 3 atoms

4 0
3 years ago
Read 2 more answers
Draw the structure of 5 bromo 1,1,1 trichloro-5 ethyl 2,3 di <br> methyl heptane
dlinn [17]

<em> </em><em>5</em><em>-</em><em>b</em><em>r</em><em>o</em><em>m</em><em>o</em><em>-</em><em>1</em><em>.</em><em>1</em><em>.</em><em>1</em><em>-</em><em>t</em><em>r</em><em>i</em><em>c</em><em>h</em><em>l</em><em>o</em><em>r</em><em>o</em><em>-</em><em>5</em><em>e</em><em>t</em><em>h</em><em>l</em><em>y</em><em>-</em><em>2</em><em>.</em><em>3</em>

methyl-heptane

3 0
3 years ago
Which oxide(s) of manganese have a mass percent of the metal that is greater than 50%?MnO MnO2 Mn2O3All of these102
Hunter-Best [27]

Answer:

All of these

Explanation:

In MnO:

mass of Mn = 55 g (as 1 mole of Mn weighs 55 g)

mass of O = 16 g    (as 1 mole of O weighs 16 g)

The mass percent of metal Mn= \frac{55}{55+16}\times100=\frac{55}{71}\times100=77.46

In MnO2:

mass of Mn = 55 g

mass of O = 2*16 = 32 g

The mass percent of metal Mn=\frac{55}{87}\times100=63.22

In Mn2O3:

mass of Mn = 2*55 = 110 g

mass of O = 3*16 = 48 g

The mass percent of metal Mn=\frac{110}{158}\times100=69.62

In all the cases the mass percent of metal is greater than 50.

5 0
3 years ago
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