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erastova [34]
3 years ago
8

The average adult heart pumps about 84. mL/s of blood at 72 beats per minute. Suppose you need to calculate how long it would ta

ke the average heart to circulate 3500.0 mL of blood. Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols.
Chemistry
1 answer:
dalvyx [7]3 years ago
5 0

Explanation:

Rate = 84mL/s

A minute has 60 seconds;

Rate = 84mL/s * 60s = 5040 mL/minute

Volume of blood in a minute = Rate * Number of beeats per minute

Volume = 5040 * 72 = 362880 mL

How long to circulate 3500ml?

1 minute = 362880mL

x = 3500 mL

x = 3500mL min / 362880mL

Math Expression:

Time to circulate 3500ml of blood (min) = 3500ml * 1 minute / Volume of blood at a rate of 84ml/s and 72 beats per minute (ml)

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andre [41]

Answer:

Atoms are single neutral particles. Molecules are neutral particles made of two or more atoms bonded together.

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Atom refers to the smallest constituent unit of a chemical element. Molecules refer to a group of two or more atoms that are held together due to chemical bonds.

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Calcium bicarbonate (Ca(HCO3)2) Ca:H:C:O = 1:2:2 ___ Lithium sulfide (Li:2s) Li:S = 2:__
Anastaziya [24]

Answer: The ratio of atoms in calcium bicarbonate ; Ca : H : C : O = 1:2:2:6.

The ratio of atoms in lithium sulfide; Li : S = 2 : 1

Explanation:

In calcium bicarbonate:Ca(HCO_3)_2

In a molecular formula of calcium carbonate there are:

Number of Calcium atoms = 1

Number of Hydrogen atom = 1 × 2 = 2

Number of Carbon atoms = 1 × 2 = 2

Number of Oxygen atoms = 3 × 2 = 6

So, Ca : H : C : O = 1 : 2 : 2 : 6

In lithium sulfide :Li_2S

In a molecular formula of lithium sulfide there are:

Number of Lithium atoms =  1 × 2 = 2

Number of Sulfur atoms = 1

So, the Li : S = 2 : 1

8 0
3 years ago
after a chemistry student made a AgNO3(small 3 at bottom) solution., she wanted to determine the molar concentration of it. if 2
Alexxandr [17]
Molar concentration = (numbet of mol Solute)/ ( volume Solution)

1) Finding
 the number of the mol solute

22.0 g AgNO3 * \frac{1 mol AgNO3}{169.91 g AgNO3} = 0.129 mol AgNO3&#10;&#10;2) 725 ml = 0.725 L&#10;&#10;&#10;

3) Molarity = \frac{number/ mol/solute}{Volume/solution} = \frac{0.129}{0.725} &#10;&#10;

Molarity= \frac{0.178 mol}{L} , &#10;&#10;or 0.178 M&#10;


3 0
3 years ago
If you initially have a volume of 4 L and a temperature of 300K. Then you decreased the volume to 2 L, what is the new temperatu
ASHA 777 [7]

Answer:

T₂ = 150 K

Explanation:

Given data:

Initial volume = 4 L

Initial temperature = 300 K

Final volume = 2 L

Final temperature = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = T₁V₂/V₁  

T₂ = 300 K × 2L / 4 L

T₂ = 600 L.K / 4 L

T₂ = 150 K

3 0
3 years ago
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