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Dvinal [7]
3 years ago
10

2Al + 3Br2 --> 2AlBr3

Chemistry
1 answer:
vlada-n [284]3 years ago
4 0
A) The limiting reactant is Al
b) Br2 is the excess reactant
c) The amount moles of AlBr3 that get produced will be equal to the number of moles of Al to begin with.
d) 0
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MariettaO [177]

Answer:

Listen in Class. The first step to passing any test is to begin preparing right there in the classroom. ...

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Explanation:

8 0
3 years ago
Select the pair that has the larger atom or ion listed first.
Sedbober [7]

Answer:

Correc option: Br^- \, , Kr

Explanation:

size of atom : it says somthing about how many shell present in a particular atom or ion and it can also be evaluated on the basis of radius of atom.

Br^- and Kr has highest number of shell as compared to other group of species .

Na ,S , Mg ,P all are from 3rd period but Kr and Br^- in the 4th period so size of species of this group will more,

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3 0
3 years ago
Which best describes the relative positions of protons, neutrons, and electrons in an atom?
Anastaziya [24]
Hello!

The center of an atom is called the nucleus; it is comprised of protons and neutrons, collectively known as nucleons. The electrons float around the nucleus in a cloud.

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6 0
3 years ago
Activity
Monica [59]

Answer:

The mass of a pure substance represents a specific number of pure substance 'molecules', as defined by molecular weight. The relative atomic mass (atomic weight) in grams/mole (g/mol) is the molar mass of a substance, which means it is the mass of one mole of that substance.

Explanation:

Hope this helps :)

8 0
3 years ago
A laboratory instructor gives a sample of amino acid powder to each of four students, i, ii, iii, and iv, and they weigh the sam
Elena L [17]
Let us differentiate accuracy from precision. Accuracy is the nearness of the measured value to the true or exact value. On the other hand, precision is the nearness of the measured values between each other. So, for precision, select the student in which the measured values are very near to each other. That would be Student III. Now, for accuracy, let's find the average for each student.

Student I: (<span>8.72g+8.74g+8.70g)/3 = 8.72 g
Student II: (</span><span>8.56g+8.77g+8.83g)/3 = 8.72 g
Student III: (</span><span>8.50g+8.48g+8.51g)/3 = 8.50 g
Student IV: (</span><span>8.41g+8.72g+8.55g)/3 = 8.56 g

From the given results, the accurate one would be Students I and II. So, we make a compromise. Even though Student III is precise, it is not accurate. If you compare between Students I and II, the more precise data would be Student I. Therefore, the answer is Student I.</span>
6 0
3 years ago
Read 2 more answers
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