Does the Carnot heat engine efficiency depends on the working fluid used in the engine? Which working fluid used in the engine w
1 answer:
Answer:
No
Explanation:
Carnot heat engine:
Carnot heat engine is an ideal heat engine for all working heat engine.It have all processes are reversible and have four processes in which twom are constant temperature process and other two constant entropy processes.
As we know that efficiency of Carnot cycle given as follows
Where
So from above expression we can say that efficiency of heat engine does not depends on the working fluids.
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Given:
frequency, f = 60.0 Hz
frequency, f' = 45.0 Hz
Solution:
To calculate max current in inductor, :
At f = 60.0 Hz
L = 0.1326 H
Now, reactance at f' = 45.0 Hz:
Now, is given by:
Therefore, max current in the inductor, = 2.13 A
Answer:
The given grammar is :
S = T V ;
V = C X
X = , V | ε
T = float | double
C = z | w
1.
Nullable variables are the variables which generate ε ( epsilon ) after one or more steps.
From the given grammar,
Nullable variable is X as it generates ε ( epsilon ) in the production rule : X -> ε.
No other variables generate variable X or ε.
So, only variable X is nullable.
2.
First of nullable variable X is First (X ) = , and ε (epsilon).
L.H.S.
The first of other varibles are :
First (S) = {float, double }
First (T) = {float, double }
First (V) = {z, w}
First (C) = {z, w}
R.H.S.
First (T V ; ) = {float, double }
First ( C X ) = {z, w}
First (, V) = ,
First ( ε ) = ε
First (float) = float
First (double) = double
First (z) = z
First (w) = w
3.
Follow of nullable variable X is Follow (V).
Follow (S) = $
Follow (T) = {z, w}
Follow (V) = ;
Follow (X) = Follow (V) = ;
Follow (C) = , and ;
Explanation:
