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3 years ago

Why does a maglev train float above the rails

Chemistry

1 answer:

kenny6666 [7]3 years ago

5 0

Answer: repelling magnets

Explanation:

The Maglev track allows the train to float above the track through the use of repelling magnets. ... This change in polarity causes the magnetic field in front of the train to pull the vehicle forward, while the magnetic field behind the train adds more forward thrust

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A 200.0 ml beaker filled with oil has a mass of 293.2 g. The mass of just the beaker is 130.2

Lelu [443]

Answer:p=m/v

p=(292.2-130.2)/200

p=0.8100g/ml

Explanation:

5 0

3 years ago

QUESTION 33 Which of the following correctly expresses 7,000,000,000 in scientific notation? 70 x 106 7 x 109 .7 x 10-7

ki77a [65]

This answer would be 7 x 109

4 0

4 years ago

How many grams of nickel (+2) are required to replace all of the silver when 15.55 grams of AgNO3 are present?

Karolina [17]

2AgNO3 + Ni2+ = Ni(NO3)2 + 2Ag+

From the reaction, it can be seen that AgNO3 and Ni2+ has following amount of substance relationshep:

n(AgNO3):n(Ni)=2:1

From the relationshep we can determinate requred moles of Ni2+:

n(AgNO3)=m/M= 15.5/169.87=0.09 moles

So, n (Ni)=n(AgNO3)/2=0.045 moles

Finaly needed mass of Ni2+ is:

m(Ni2+)=nxM=0,045x58.7=2.64g

8 0

3 years ago

A student weighs out 3.68 grams of cobalt (II) chloride to do an experiment with. How many moles of is this?

leva [86]

Answer:

0.029mol

Explanation:

from

n=m÷mr

where

n is number of moles

m is mass

mr is molar mass

8 0

3 years ago

Glucose (C6H12O6) can be fermented to yield ethanol (CH3CH2OH) and carbon dioxide (CO2). C6H12O6⟶2CH3CH2OH+2CO2 The molar mass o

jekas [21]

Answer:

The % yield is 74.45 %

Explanation:

Step 1: The balanced equation

C6H12O6⟶2CH3CH2OH+2CO2

Step 2: Data given

Molar mass glucose = 180.15 g/mol

Molar mass of ethanol = 46.08 g/mol

Molar mass of carbon dioxide = 44.01 g/mol

Mass of glucose = 61.5 grams

Mass of ethanol = 23.4 grams

Step 3: Calculate moles of glucose

Moles glucose = Mass glucose / Molar mass of glucose

Moles glucose = 61.5 grams / 180.15 g/mol

Moles glucose = 0.341 moles

Step 4: Calculate moles of ethanol

1 mole of glucose consumed, produces 2 moles of ethanol and 2 moles of CO2

0.341 moles of glucose, will produce 2*0.341 = 0.682 moles of ethanol

Step 5: Calculate mass of ethanol

Mass ethanol = moles ethanol * Molar mass ethanol

Mass ethanol = 0.682 moles * 46.08 g/mol

Mass ethanol = 31.43 grams = theoretical mass

Step 6: Calculate % yield

% yield = actual mass / theoretical mass

% yield = (23.4 grams / 31.43 grams) * 100%

% yield = 74.45 %

The % yield is 74.45 %

7 0

4 years ago