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3 years ago

The x component of vector is 8.7 units, and its y component is -6.5 units. The magnitude of is closest to

Physics

1 answer:

irina1246 [14]3 years ago

5 0

Answer:

F = 10.86 units

Explanation:

The magnitude of a vector in terms of the magnitude of its rectangular components is given by the following formula:

F = √(Fₓ² + Fy²)

where,

F = Magnitude of the Vector = ?

Fₓ = magnitude of the x-component of vector = 8.7 units

Fy = magnitude of y component of vector = - 6.5 units

Therefore, using these values in the equation, we get:

F = √[(8.7 units)² + (- 6.5 units)²]

F = √(117.94 units²)

F = 10.86 units

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A frog is at the bottom of a 17-foot well. Each time the frog leaps, it moves up 3 feet. If the frog has not reached the top of

docker41 [41]

Answer:

The frog takes 8 jumps to reach top of well

Explanation:

Given data

Frog at bottom=17 foot

Each time frog leaps 3 feet

Frog has not reached the top of the well, then the frog slides back 1 foot

To Find

Total number of leaps the frog needed to escape from well

Solution

in 1 jump distance jumped=3+(-1)

=2 feet

=2×1 feet

The "-1" is because the frog goes back

Now After 2 jumps the distance jumped as:

Distance Jumped=2+2

Distance Jumped=2*2

=4 feet

Similarly after 7 jumps

Distance Jumped=2+2+......+2

Distance Jumped=2*7

=14 feet

Now after 8th jump the frog climbs but doesnot slide back as it is reached to the top of well.

Distance Jumped=(Distance Jumped after 7 jumps)+3

=14+3

=17 feet

The frog takes 8 jumps to reach top of well

7 0

3 years ago

A 0.750kg block is attached to a spring with spring constant 13.5N/m . While the block is sitting at rest, a student hits it wit

vazorg [7]

Answer:

A)A=0.075 m

B)v= 0.21 m/s

Explanation:

Given that

m = 0.75 kg

K= 13.5 N

The natural frequency of the block given as

$\omega =\sqrt{\dfrac{K}{m}}$

The maximum speed v given as

$v=\omega A$

A=Amplitude

$v=\sqrt{\dfrac{K}{m}}\times A$

$0.32=\sqrt{\dfrac{13.5}{0.75}}\times A$

A=0.075 m

A= 0.75 cm

The speed at distance x

$v=\omega \sqrt{A^2-x^2}$

$v=\sqrt{\dfrac{K}{m}}\times \sqrt{A^2-x^2}$

$v=\sqrt{\dfrac{13.5}{0.75}}\times \sqrt{0.075^2-(0.075\times 0.75)^2}$

v= 0.21 m/s

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3 years ago

If Abdul pedals his 20 kg bike with a force of 100 N, what will the bike’s acceleration be? The formulas above may be helpful in

Scorpion4ik [409]

Answer:

5 m/s/s

Explanation:

F = ma

100 = 20a

100/20 = a

a = 5 m/s/s

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3 years ago

Which hand is negatively charged? ОА ОВ. Ос. OD

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Answer is OB
Answer is OB
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A student claims "everything falls at the same acceleration rate on the Moon, where there is no air or friction," how would you

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Now let’s say you’re on the Moon. If you were to drop a hammer and a feather from the same height, which would hit the ground first?

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So yeah, the student is right. Galileo gave us this theory long ago.

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3 years ago