Answer:
F = 8.6 10⁻¹² N
Explanation:
For this exercise we use the law of conservation of energy
Initial. Field energy with the electron at rest
Em₀ = U = q ΔV
Final. Electron with velocity, just out of the electric field
Emf = K = ½ m v²
Em₀ = Emf
e ΔV = ½ m v²
v =√ 2 e ΔV / m
v = √(2 1.6 10⁻¹⁹ 51400 / 9.1 10⁻³¹)
v = √(1.8075 10¹⁶)
v = 1,344 10⁸ m / s
Now we can use the equation of the magnetic force
F = q v x B
Since the speed and the magnetic field are perpendicular the force that
F = e v B
F = 1.6 10⁻¹⁹ 1.344 10⁸ 0.4
For this exercise we use the law of conservation of energy
Initial. Field energy with the electron at rest
Emo = U = q DV
Final. Electron with velocity, just out of the electric field
Emf = K = ½ m v2
Emo = Emf
.e DV = ½ m v2
.v = RA 2 e DV / m
.v = RA (2 1.6 10-19 51400 / 9.1 10-31)
.v = RA (1.8075 10 16)
.v = 1,344 108 m / s
Now we can use the equation of the magnetic force
F = q v x B
Since the speed and the magnetic field are perpendicular the force that
F = e v B
F = 1.6 10-19 1,344 108 0.4
F = 8.6 10-12 N
Answer:
Answer is D. 8.04 x 10^4 J
Explanation:
1. D
2. A
3. D
4. B
5. C
6. B
7. D
8. C
9. B
10. D
All correct i promise you that
Options a to c can be the reasons for scientific models.
But to primarily answer scientific questions,that would require an empirical and experimental approach and not use of models.
Though after getting the answers, models can be built to further explain the answers.
<span>d. answer scientific questions.</span>
Answer: the answer is most likely that the mirror is 120 cm tall as well
Explanation:mark brainliest PLEASE.
Answer:
The taken is 
Explanation:
Frm the question we are told that
The speed of car A is 
The speed of car B is 
The distance of car B from A is 
The acceleration of car A is 
For A to overtake B
The distance traveled by car B = The distance traveled by car A - 300m
Now the this distance traveled by car B before it is overtaken by A is

Where
is the time taken by car B
Now this can also be represented as using equation of motion as

Now substituting values

Equating the both d

substituting values




Solving this using quadratic formula we have that
