Answer:
(A)
A cup placed on a table won't float away
The stretching force acting on the second wire, given the data is 588 N
<h3>Data obtained from the question</h3>
- Radius of fist wire (r₁) = 3.9×10⁻³ m
- Force of first wire (F₁) = 450 N
- Radius of second wire (r₂) = 5.1×10⁻³ m
- Force of second wire (F₂) =?
<h3>How to determine the force of the second wire</h3>
F₁ / r₁ = F₂ / r₂
450 / 3.9×10⁻³ = F₂ / 5.1×10⁻³
cross multiply
3.9×10⁻³ × F₂ = 450 × 5.1×10⁻³
Divide both side by 3.9×10⁻³
F₂ = (450 × 5.1×10⁻³) / 3.9×10⁻³
F₂ = 588 N
Learn more about spring constant:
brainly.com/question/9199238
#SPJ1
Answer:
(D) parasite........................
Answer:
v = 45.37 m/s
Explanation:
Given,
angle of inclination = 8.0°
Vertical height, H = 105 m
Initial K.E. = 0 J
Initial P.E. = m g H
Final PE = 0 J
Final KE = 
Using Conservation of energy
v = 45.37 m/s
Hence, speed of the skier at the bottom is equal to v = 45.37 m/s
Potential Energy (P.E) = Mass x
Acceleration due to Gravity x Altitude. Putting this value in the above equation we get, Dimensional Formula of
Potential energy= M1L2T-2.
