g What is the specific heat of silver? The molar heat capacity of silver is 25.35 J/mol⋅∘C. How much energy would it take to rai
1 answer:
Answer:
38.6 J
Explanation:
c = molar heat capacity of silver = 25.35 J/(mol °C)
m = given mass of silver = 9.00 g
M = Molar mass of silver = 108 g
n = Number of moles of silver
Number of moles of silver are given as
n = 0.0833
Q = Energy needed to raise the temperature
ΔT = Change in temperature = 18.3 °C
Energy needed to raise the temperature is given as
Q = n c ΔT
Q = (0.0833) (25.35) (18.3)
Q = 38.6 J
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Answer:
(a) the final velocity of the cart is 0.857 m/s
(b) the impulse experienced by the package is 21.43 kg.m/s
(c) the fraction of the initial energy lost is 0.71
Explanation:
Given;
mass of the package, m₁ = 10 kg
mass of the cart, m₂ = 25 kg
initial velocity of the package, u₁ = 3 m/s
initial velocity of the cart, u₂ = 0
let the final velocity of the cart = v
(a) Apply the principle of conservation of linear momentum to determine common final velocity for ineleastic collision;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
10 x 3 + 25 x 0 = v(10 + 25)
30 = 35v
v = 30 / 35
v = 0.857 m/s
(b) the impulse experienced by the package;
The impulse = change in momentum of the package
J = ΔP = m₁v - m₁u₁
J = m₁(v - u₁)
J = 10(0.857 - 3)
J = -21.43 kg.m/s
the magnitude of the impulse experienced by the package = 21.43 kg.m/s
(c)
the initial kinetic energy of the package is calculated as;
the final kinetic energy of the package;
the fraction of the initial energy lost;
Answer:
355 m/s
Explanation:
Distance = 605 km
Initial speed = = 284 m/s
Final velocity = = 426 m/s
Average speed = ?
There is two method two find average speed. In first method, using 3rd equation of motion, we find acceleration.
Then using first equation of motion, we find time
Then using the formula of average velocity, we find average velocity
Second method is very simple
355 m/s