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sukhopar [10]
3 years ago
5

Which of the following provides evidence that Earth's Moon is rotating and revolving at the same rate?

Physics
1 answer:
kkurt [141]3 years ago
6 0

B. We can see only one side of the Moon from Earth.


( we only see one side of the moon because the moon rotates around the Earth)

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Kiera, a 330 N girl, steps in water that someone spilt on the floor. The coefficient of kinetic friction between Kiera and the f
shutvik [7]

Answer:

<em>The force of kinetic friction between Kiera and the floor is 9.24 N</em>

Explanation:

<u>Friction Force</u>

When an object is moving and encounters friction in rough surfaces, it loses acceleration and/or velocity because the friction force opposes motion.

The friction force when an object is moving on a horizontal surface is calculated by:

Fr=\mu N

Where μ is the coefficient of static or kinetics friction and N is the normal force.

If no forces other then the weight and the normal are acting upon the y-direction, then the weight and the normal are equal in magnitude:

N = W

Thus, the friction force is:

Fr=\mu W

Kiera, the W=330 N girl steps in water that has a coefficient of friction of μ=0.028 with the floor.

The kinetic friction force is:

Fr = 0.028*330

Fr = 9.24 N

The force of kinetic friction between Kiera and the floor is 9.24 N

3 0
3 years ago
A substance that cannot be broken into simpler elements ia an
Anastaziya [24]
Element. element cannot be simplerfide 
3 0
3 years ago
Plane-polarized light is incident on a single polarizing disk, with the direction of E0 parallel to the direction of the transmi
Vladimir [108]

Answer: 65.9^{\circ}

Explanation:

Given

Intensity must be reduced by a factor of 6

Intensity is given by I=I_o\cos ^2\theta\\

Substitute I by \frac{I_o}{6}

\Rightarrow \dfrac{I_o}{6}=I_o\cos ^2\theta\\\\\Rightarrow \cos^2\theta =\dfrac{1}{6}\\\\\Rightarrow \cos \theta=\dfrac{1}{\sqrt{6}}\\\\\Rightarrow \theta=65.9^{\circ}

So, the disk must be rotated by an angle of 65.9^{\circ} .

7 0
2 years ago
A ball is thrown from ground level so as to just clear wall 4m height at distance 4m from wall and falls 14 m from wall . Veloci
kolbaska11 [484]
Ok, this is a 2d kinematics problem,  the falls 14 m part is confusing, I think it means in the x direction, but you don't need it anyway.

If we know it goes 4m into the air, we know  d = 4m (height of wall), we also know the acceleration a=-9.8m/s^2 (because gravity) and that the vertical velocity when it just clears the wall will be 0 m/s, which we'll call our final velocity (Vf). Using Vf^2 = Vi^2 +2a*d, we can solve this for Vi and drop Vf because it's zero to get: Vi = sqrt(-2ad), plug in numbers (don't forget a is negative) and you get 8.85 m/s in the vertical direction. The x-direction velocity requires that we solve the y-direction for time, using Vf= Vi + at, we solve for t, getting t= -Vi/a, plug in numbers t= -8.85/-9.8 = 0.9 s. Now we can use the simple v = d/t (because x-direction has no acceleration (a=0)), and plug in the distance to the wall and the time it takes to get there v = (4/.9) = 4.444 m/s, this is the velocity in the x direction, we use Pythagoras' theorem to find the total velocity, Vtotal = sqrt(Vx^2 + Vy^2), so Vtotal = sqrt(8.85^2+4.444^2) = 9.9m/s. Yay physics!
8 0
3 years ago
A substance has a volume of 10.0 cm3 and a mass of 89 grams. What is its density?
vovikov84 [41]
Density = mass / volume

D = 89 / 10.0

D = 8.9 g/cm³

hope this helps!
8 0
3 years ago
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