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s344n2d4d5 [400]
3 years ago
6

When you hold a rectangular object how does the area of the side that is resting on your hand affects the pressure and the force

that the object exerts
Physics
1 answer:
Naily [24]3 years ago
4 0

Answer:

A rectangular object may have different areas for different sides.

If that object is placed on a hand, the area of its side does not affects the Force. However the pressure it puts on the hand is affected by the area.

Explanation:

The Force that object applies on the hand is given as the product of its mass and gravitational acceleration 'g'. Hence area does not affect the Force and it is constant.

F = mg

Pressure is defined as the Force per unit area.

P = F/A

As the surface area decreases and Force remains constant, the pressure on the hand increases and vice versa.

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An emission ray has a frequency of 5.10 × 10¹Ê Hz. Given that the speed of light is 2.998 × 10§ m/s, what is the wavelength of t
scoundrel [369]
The answer is 5.88 · 10⁻⁷<span> m.</span>

To calculate this we will use the light equation:

v = λ · f,
where:
v - the speed of light (units: m/s)
<span>λ - the wavelength of the ray (units: m)
</span>f - the frequency of the ray (units: Hz = 1/s <span>since Hz means cycles per second (f=1/T))
</span>
It is given:
f = 5.10 · 10¹⁴ Hz = 5.10 · 10¹⁴<span> 1/s
v = 2.998 </span>· 10⁸<span> m/s
</span><span>λ = ?
</span>
If v = λ · f, then λ = v ÷ f:
λ = 2.998 · 10⁸ m/s ÷ 5.10 · 10¹⁴ 1/s
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Several forces act on an object at rest. It is known that the sum of the forces acting on the object is zero. Which statement is
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Answer:

When net force of zero acting on a ball which is at rest , then the object center of mass will not accelerate , but the object may begin to rotate .

Explanation:

Here when there is an object where several forces are acing upon  are zero then the center of mass will not accelerate because we know that

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