The angular momentum of an electron in the third Bohr orbit of a hydrogen atom is given by mvr=3h÷2π
<h3>What is momentum?</h3>
Momentum is defined as the amount of motion occurring in something that is moving, or the force that drives something forward to keep it moving.
Bohr never assumed stable electronic orbits with the electronic angular momentum quantized as
l=mvr = 
Quantization of angular momentum means that the radius of the orbit and the energy will be quantized as well.
Bohr assumed that the discrete lines seen in the spectrum of the hydrogen atom were due to transitions of an electron from one allowed orbit/energy to another.
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Answer:
No. While gold would not react with a silver nitrate solution, nickel would.
Explanation:
Refer to the metal reactivity series.
Reactivity: 
.
Gold is positioned after silver in the reactivity series, meaning that gold is typically less reactive than silver. Thus, gold would not react with a solution of silver ions to produce silver metal.
However, since nickel is positioned before silver in the reactivity series, it is expected that nickel would react with silver ions in this solution to produce silver metal.
Thus, if the silver nitrate solution comes into contact with the two rings, the nickel ring would likely react with the solution, the gold ring would not.
Answer:
8.6 mol
Explanation:
number of moles = molar concentration x volume in litre
number of moles = 2.33 M x 3.70 L = 8.6 mol
Answer:
[S₂] = 1.27×10⁻⁷ M
Explanation:
2 H₂S(g) ⇄ 2 H₂(g) + S₂(g), Kc=1,625x10⁻⁷
The equation of this reaction is:
1,625x10⁻⁷ = ![\frac{[H_2]^2[S_2]}{[H_{2}S]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH_2%5D%5E2%5BS_2%5D%7D%7B%5BH_%7B2%7DS%5D%5E2%7D)
The equilibrium concentrations are:
[H₂S] = 0,162 - 2x
[H₂] = 0,184 + 2x
[S₂] = x
Replacing:
1,625x10⁻⁷ = ![\frac{[0,184+2x]^2[x]}{[0,162-2x]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B0%2C184%2B2x%5D%5E2%5Bx%5D%7D%7B%5B0%2C162-2x%5D%5E2%7D)
Solving:
4x³ + 0,736x² + 0,033856x - 4,3x10⁻⁹
x = 1.27×10⁻⁷
Thus, concentration of S₂ is:
<em>[S₂] = 1.27×10⁻⁷ M</em>
