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3 years ago

The pH of acid J is 4. The pH of acid K is 6. How much more acidic is acid J than acid K?

Chemistry

1 answer:

marysya [2.9K]3 years ago

3 0

Answer:

100 Times more Acidic

Explanation:

The pH scale is logarithmic in every 10. So, from 4 to 5 is 10 times less acidic. From 5 to 6 is another 10 times less acidic. So in total, it is 100 times less acidic.

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Two identical containers, one red and one yellow, are inflated with different gases at the same volume and pressure. Both contai

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Answer:

Explanation:

Here we're dealing with the root mean square velocity of gases. We'll provide the formula in order to calculate the root mean square velocity of a gas:

$v_{rms}=\sqrt{\frac{3RT}{M}}$

Here:

$R = 8.314 \frac{J}{K mol}$ is the ideal gas law constant;

$T$ is the absolute temperature in K;

$M$ is the molar mass of a compound in kg/mol.

We know that the gas from the red container is 4 times faster, as it takes 4 times as long for the yellow container to leak out, this means:

$\frac{v_{rms, red}}{v_{rms, yellow}} = 4$

We also know that the temperature of the red container is twice as large:

$\frac{T_{red}}{T_{yellow}} = 2$

Write the ratio of the velocities and substitute the variables:

$\frac{v_{rms, red}}{v_{rms, yellow}}=\frac{\sqrt{\frac{3RT_{red}}{M_{red}}}}{\sqrt{\frac{3RT_{yellow}}{M_{yellow}}}}=4$

Then:

$\frac{\sqrt{\frac{3RT_{red}}{M_{red}}}}{\sqrt{\frac{3RT_{yellow}}{M_{yellow}}}}=\sqrt{\frac{3RT_{red}}{M_{red}}\cdot \frac{M_{yellow}}{3RT_{yellow}}}=\sqrt{\frac{T_{red}}{T_{yellow}}\cdot \frac{M_{yellow}}{M_{red}}}=4$

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$16 = \frac{T_{red}}{T_{yellow}}\cdot \frac{M_{yellow}}{M_{red}}$

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I hope my answer has come to your help. God bless and have a nice day ahead!
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