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4 years ago

At what point is base no longer added during a titration

1 answer:

8 0

When you doing a titration, you need to use an indicator to confirm whether the reaction is completed. When the indicator has the color change and will not change back in one minute, the reaction is finished and you don't need to add more.

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Plz answer this fast... will mark ur answer as brainliest

Xelga [282]

Answer:

When fuels are incompletely burnt, they release carbon monoxide gas into the atmosphere. This gas is very dangerous as it is poisonous in nature

Explanation:

7 0

3 years ago

Read 2 more answers

Upon adding solid potassium hydroxide pellets to water the following reaction takes place: KOH(s) → KOH(aq) + 43 kJ/mol Answer t

nekit [7.7K]

Answer:

a) Warmer

b) Exothermic

c) -10.71 kJ

Explanation:

The reaction:

KOH(s) → KOH(aq) + 43 kJ/mol

It is an exothermic reaction since the reaction liberates 43 kJ per mol of KOH dissolved.

Hence, the dissolution of potassium hydroxide pellets to water provokes that the beaker gets warmer for being an exothermic reaction.

The enthalpy change for the dissolution of 14 g of KOH is:

$n = \frac{m}{M}$

<u>Where:</u>

m: is the mass of KOH = 14 g

M: is the molar mass = 56.1056 g/mol

$n = \frac{m}{M} = \frac{14 g}{56.1056 g/mol} = 0.249 mol$

The enthalpy change is:

$\Delta H = -43 \frac{kJ}{mol}*0.249 mol = -10.71 kJ$

The minus sign of 43 is because the reaction is exothermic.

I hope it helps you!

5 0

3 years ago

After the end of a normal inspiration, the volume of air in the lungs is about 2.8 L. Normally quiet inspiration is driven by a

vodka [1.7K]

Answer:

The Volume of the lungs that would produce 2 mmHg pressure decrease is

$V_2 = 2.81 \ L$

Explanation:

From the question we are told that

The volume of air in the lungs is $V = 2.8 \ L$

The pressure difference for quit normal inspiration is $P = 2 \ mmHg$

The temperature of air in the lungs $T = 37^oC$

The pressure after normal expiration is at $T = 760 \ mmHg$

From ideal gas law we have that

$PV= nRT$

Now since nRT is constant we have that

$P_1 V_1 = P_2 V_2$

As the pressure decreased by 2 mmHg the volume becomes

$V_2 = \frac{P_1 V_1}{P_2}$

$V_2 = \frac{2.8 * 760}{758}$

$V_2 = 2.81 \ L$

3 0

3 years ago

What drives the flow of energy in cycling of matter in the atmosphere

nalin [4]

The earths rotation if I’m not mistaken

4 0

3 years ago

What is the oxidation number of Ni in NiO

galben [10]

Answer:

Explanation:

Nickel (II) oxide, or NiO, is an ionic compound. Recalling a few rules of determining the oxidation number of substances:

1. Oxidation numbers of elements in ionic compounds are usually their own ionic charge

2. The total oxidation number of a neutral compound should be 0

And,

3. The oxidation number of oxygen in most cases is -2.

Therefore, since O in NiO has a oxidation number of -2, and nickel (II) ion usually has a charge of 2+, the oxidation number of Ni in NiO is +2 (always remember to put the positive sign in front of the number)

4 0

4 years ago