A + H means that energy is released from a reaction. True or False

fish give off the compound ammonia which has a pH above 7 to which class of compounds does ammonia belong

jasenka [17]

Answer:
The compound ammonia given by fish is alkaline

Explanation:
We can classify elements/compounds based on their pH values into three types:
acids: these are compounds having pH value lower than 7
neutral: these are compounds having pH value equal to 7
alkalies: these are compounds having pH values higher than 7

This is shown in the attached image

We are given that the pH of the compound ammonia generated by the fish is above 7.
According to the above explanation, compound ammonia would be an alkaline compound.

Hope this helps :)

5 0

3 years ago

Which statement is true about a polyatomic ion?

nataly862011 [7]

The correct answer is that it is made of atoms that are covalently bonded together. Hope this helps.

4 0

4 years ago

1.00 mole of oxygen at 60 degrees celcius and 5 bar is flowing through a 20cm diameter pipe (inner diameter). What is the veloci

jeka94

Answer:

u = 0.176 m/x

Explanation:

∴ n O2 = 1 mol

∴ mass O2 = 1 mol * 32 g/mol = 32 g

∴ T = 60°C = 333 K

∴ P = 5 bar

⇒ V = RTn/P = (83.14 bar.cm³/mol.K)*(333 K)*(1 mol))/(5 bar)

⇒ V = 5537.124 cm³

∴ d = 20cm

⇒ A = (1/4π)*d² = 314.16 cm²

velocity of the gas (m/x):

u = m / ρ*A
let time (t) = x sec

∴ ρ = 32 g / 5537.124 cm³ = 5.78 E-3 g/cm³

∴ mass flow rate (m) = 32g / x

⇒ u = (32 g/x) / (( 5.78 E-3 g/cm³)*(314.16cm²))

⇒ u = 17.625 cm/x * ( m/100cm) = 0.176 m/x

4 0

3 years ago

In experiment 1, how many moles of benzoic acid are present? how many moles of sodium bicarbonate are contained in 1 ml of a 10%

nexus9112 [7]

First, let us calculate the moles of solute or sodium bicarbonate is in the 1 ml solution.

moles = 1 mL * (1 g / 9 mL) = 0.11 moles

The molar mass of sodium bicarbonate is 84 g/mol, therefore the mass is:

mass = 0.11 moles * 84 g/mol

mass = 9.33 g

6 0

3 years ago

Given the propane molecule C3H8(g)! a) What is the balanced equation for the combustion of propane in O2?(20 pts.) b) What is th

lubasha [3.4K]

Answer:

The answer to your question is below

Explanation:

Propane = C₃H₈

Process

1.- Write the chemical reaction

C₃H₈ + O₂ ⇒ CO₂ + H₂O

balanced chemical reaction

C₃H₈ + 5O₂ ⇒ 3CO₂ + 4H₂O

Reactants Elements Products

3 C 3

8 H 8

10 O 10

b) Standard enthalpy

Propane -104.7 kJ/mol

Oxygen 0 kJ/mol

Carbon dioxide -393.5 kJ/mol

Water -241.8 kJ/mol

ΔH° = ∑ΔH° products - ∑H° reactants

ΔH° = 3(-393.5) + 4(-241.8) - [(-104.7) + 0]

-Simplification

ΔH° = -1180.5 kJ/mol - 967.2 kJ/mol + 104.7 kJ/mol

ΔH° = - 2042.5 kJ/mol

This reaction is exothermic because ΔH° is negative.

4 0

3 years ago