I know i did part a correctly. heres what i did: momentum is conserved: m1 * u - m2 * u = m2 * v or (m1 - m2) * u = m2 * v Also, for an elastic head-on collision, we know that the relative velocity of approach = relative velocity of separation (from conservation of energy), or, for this problem, 2u = v Then (m1 - m2) * u = m2 * 2u m1 - m2 = 2 * m2 m1 = 3 * m2 m1 is the sphere that remained at rest (hence its absence from the RHS), so m2 = 0.3kg / 3 m2 = 0.1 kg b) this part confuses me, heres what i did (m1 - m2) * u = m2 * v (.3kg - .1kg)(2.0m/s) = .1kg * v .4 kg = .1 v v = 4 m/s What my teacher did: (.3g - .1g) * 2.0m/s = (.3g + .1g) * v I understand the left hand side but i dont get the right hand side. Why is m1 added to m2 when m1 is at rest which makes its v = zero?? v = +1.00m/s since the answer is positive, what does that mean? Also, if v was -1.00m/s what would that mean? thanks!
<span>Reference https://www.physicsforums.com/threads/elastic-collision-with-conservation-of-momentum-problem.651261...</span>
In a block and tackle, some friction in the pulleys will reduce the mechanical advantage of the machine. To include friction in a calculation of the mechanical advantage of a block and tackle, divide the weight of the object being lifted by the weight necessary to lift it.
Hope this helps
1st find the slope of the line:
(11-5)/(8.2-2.3) = 6/5.9 = 1.01
Find the equation of the line:
y - 5 = 1.01(x - 2.3)
y - 5 = 1.01x - 2.323
y = 1.01x + 2.667
Now set x to 20
y = 1.01(20) + 2.667
y = 20.2 + 2.667
y = 22.867 floors ~ 23 floors
Answer:
Past
I walked home.
She studied.
He made a list.
Present
She walks home.
They leave the door open.
Future
She will walk home.
It will open next week.
Explanation:
Answer:
Efficiency of this process is 30 %.
Explanation:
It is given that,
Electric energy used by the machine, 
The potential energy of the machine is increased, 
The efficiency of this machine is given by :
So, the efficiency of this process is 30 %. Hence, this is the required solution.
