Question

The table shows the charges and the distance between five different pairs of objects.

Answer 1

Answer : Y > W > X > Z

Explanation :

The electrostatic force is given by :

$F=k\dfrac{q_1q_2}{d^2}$

k is the electrostatic constant

q₁ and q₂ are charges

d is the distance between them

We will calculate forces one by one :

$F=k\dfrac{q.q}{d^2}=\dfrac{kq^2}{d^2}$

$W=k\dfrac{q.2q}{d^2}=\dfrac{2kq^2}{d^2}=2F$

$X=k\dfrac{q.q}{(2d)^2}=\dfrac{kq^2}{4d^2}=\dfrac{F}{4}$

$Y=k\dfrac{3q.q}{d^2}=\dfrac{3kq^2}{d^2}=3F$

$Z=k\dfrac{q.q}{(3d)^2}=\dfrac{kq^2}{9d^2}=\dfrac{F}{9}$

So, the force from greatest to least will be :

Y > W > X > Z

So, the correct option is (B)

Answer 2

B. Y,W,X,Z is the answer, Hope it helps