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zalisa [80]
3 years ago
10

You have 100 mL of a solution of benzoic acid in water; the amount of benzoic acid in the solution is estimated to be about 0.30

g. The distribution coefficient of benzoic acid in diethyl ether and water is approximately 10. Calculate the amount of acid that would be left in the water solution after four 20-mL extractions with ether.
Chemistry
1 answer:
dimaraw [331]3 years ago
3 0

Answer:

0.00370 g

Explanation:

From the given information:

To determine the amount of acid remaining using the formula:\dfrac{(final \ mass \ of \ solute)_{water}}{(initial \ mass \ of \ solute )_{water}} = (\dfrac{v_2}{v_1+v_2\times k_d})^n

where;

v_1 = volume of organic solvent = 20-mL

n = numbers of extractions = 4

v_2 = actual volume of water = 100-mL

k_d = distribution coefficient = 10

∴

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +20 \ ml \times 10})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{100 \ ml}{100 \ ml +200 \ ml})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = (\dfrac{1}{3})^4

\dfrac{(final \ mass \ of \ solute)_{water}}{0.30  \ g} = 0.012345

Thus, the final amount of acid left in the water = 0.012345 * 0.30

= 0.00370 g

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Step 4:

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2 years ago
A compound is found to contain 7.962 % silicon , 20.10 % chlorine , and 71.94 % iodine by mass. to answer the question, enter th
arlik [135]
Empirical   formula  is  calculated   as  follows

calculate  the  moles  of  each  element,  that  is   %  composition/  molar  mass
molar  masses  (  Si=  28.09g/mol ,  Cl=  35.5  g/mol,  I=126.9 g/mol)

moles  of  silicon =  7.962/28.09g/mol=  0.283  moles
moles  of  chlorine =  20.10 / 35.5g/mol =  0.566  moles
moles  of  iodine=  71.94 / 126.9  g/mol=  0.567  moles

divide  each  mole   with  smallest    mole  (0.283)
that  is    silicon =  0.283/0.283= 1 mole
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empirical  formula  is  therefore=  SiCl2I2


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