To determine the charge of the iron, you must know the charge from the oxygen. An oxygen ion has a -2 charge. Therefore, 3 oxygen ions have -6 charge. We know that charges must cancel out. If it were Fe+2 in the compound, the overall charge would be -2, which isn’t correct. So, we can conclude that it is Fe+3 found in iron (III) oxide.
Answer:
atomic number- 42
chemical number- 96
number of protons-18
atomic mass-96
number of eletrons-42
number of valence eletrons- 1, 2, 13, or 18. (sorry i forgot)
nummber of shells in n=3 shell-18
number of neutrons-54
Explanation:
well i just know the periodic table by heart and thats how i got the answer XD
Answer:
![[PCl_3]=[Cl_2]=0.068M](https://tex.z-dn.net/?f=%5BPCl_3%5D%3D%5BCl_2%5D%3D0.068M)
![[PCl_5]=0.385M](https://tex.z-dn.net/?f=%5BPCl_5%5D%3D0.385M)
Explanation:
Hello!
In this case, since the equilibrium expression for the considered equation is:
![Kc=\frac{[PCl_5]}{[Cl_2][PCl_3]}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BPCl_5%5D%7D%7B%5BCl_2%5D%5BPCl_3%5D%7D)
Which can be written in terms of the reaction extent and the ICE chart and the initial concentrations of 0.453 M as shown below:

We can solve for x as follows:

In such a way, we obtain the following concentrations at equilibrium:
![[PCl_3]=[Cl_2]=0.453M-0.385M=0.068M](https://tex.z-dn.net/?f=%5BPCl_3%5D%3D%5BCl_2%5D%3D0.453M-0.385M%3D0.068M)
![[PCl_5]=0.385M](https://tex.z-dn.net/?f=%5BPCl_5%5D%3D0.385M)
Best regards!
To determine the density, we use the following formula:

mass= 2.813 grams
volume= ?
we need to first calculate the volume before we can solve for the density. since the question states that the sample has a spherical shape, we can use the volume formula of spheres to find it.

radius (r)=

=

let's plug in the values
V=

we need to change the

to

using the following conversion
1 cm= 10 mm

now we can find the density.
density= 2.813 grams/ 0.268 cm=
10.5 g/cm3