2 years ago

Marty did 24 chin-ups. Elise did 5/8 as many chin-ups as Marty. How many chin-ups did Elise do?

Mathematics

2 answers:

lbvjy [14]2 years ago

3 0

Answer:

Step-by-step explanation:

IrinaK [193]2 years ago

3 0

Answer:

Step-by-step explanation:

24 * 5/8 = 15

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How to turn 12/25 in precent

Len [333]

Answer:

48%

Step-by-step explanation:

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$\frac{12}{25}*100$

$= \frac{}{} 12*4$

= 48%

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3 years ago

Kathy used 15 ounces of chocolate in her cookies. Cindy used 15% more chocolate in her cookies. How many ounces did Cindy use? (

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3 years ago

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2 years ago

A college football coach has decided to recruit only the heaviest 15% of high school football players. He knows that high school

Alla [95]

Answer:

The coach should start recruiting players with weight 269.55 pounds or more.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 225 pounds

Standard Deviation, σ = 43 pounds

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.15

$P( X > x) = P( z > \displaystyle\frac{x - 225}{43})=0.15$

$= 1 -P( z \leq \displaystyle\frac{x - 225}{43})=0.15$

$=P( z \leq \displaystyle\frac{x - 225}{43})=0.85$

Calculation the value from standard normal z table, we have,

$P(z < 1.036) = 0.85$

$\displaystyle\frac{x - 225}{43} = 1.036\\\\x = 269.548 \approx 269.55$

Thus, the coach should start recruiting players with weight 269.55 pounds or more.

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3 years ago