The specific heat, c is 0.75 J/g°C
<u>Explanation:</u>
Heat or Energy, Q = 1500J
Mass, m = 50g
T1 = 0°C
T2 = 40°C
Specific Heat, c = ?
We know,
Q = mcΔT
Q = mc(T2-T1)
1500 = 50 X c X (40-0)
1500 = 50 X c X 40
c = 1500/ 2000
c = 0.75 J/g°C
Therefore, the specific heat, c is 0.75 J/g°C
<span>Barometric pressure is just the same as
atmospheric pressure. It is called barometric pressure because the instrument
used to measure is called barometer. It is the pressure exerted by the air at a
certain altitude. Since it is the pressure exerted by the air, it is also known
as the weight of the air above the Earth. Depending on the altitude at which
the measurement is done, barometric or atmospheric pressure varies, but the
barometric pressure at sea level is 1 atm (atmosphere). It is equivalent to
101325 Pa (Pascal), 760 torr, 760 mm Hg and 1.01325 bar.</span>
Answer:
Explanation:
<u>1) Determine the molar mass of the heptane</u>
element # of atoms atomic mass total mass
C 7 12.011 g/mol 7×12.011 g/mol = 84.077 g/mol
H 16 1.008 g/mol 16×1.008 g/mol = 16.128 g/mol
-------------------
Molar mass = 100.205 g/mol
<u>2) Percent of carbon, %</u>
- % = (mass of element / molar mass )×100
= (84.077 g/mol / 100.205 g/mol )×100 = 83.83 %
- Round to two significant figures: 84% ← answer
Here, I took this straight from the notes I took back when I learned this. If you need any more clarification, just say so.
<span>Bohr: Planetary model<span>Theorized that E- travel in specific orbits around the nucleus.The further an E- is from the nucleus, the higher its “energy.”The number of E- in the outermost orbital<span> determines the reactivity of an element.</span>
Bohr's model was a nucleus with concentric circles going around it representing the energy levels (where the electrons are in the atom). He was the first to demonstrate that the electrons in an atom orbit the nucleus, rather than stay in a consistent position. Google "Bohr Atomic Model" if you need any visual clarification. Hope I helped, and let me know if you need anything else!</span></span>
