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egoroff_w [7]
3 years ago
14

(a) Calculate how much work is required to launch a spacecraft of mass m from the surface of the earth (mass mE, radius RE) and

place it in a circular low earth orbit, that is, an orbit whose altitude above the earth's surface is much less than RE. (As an example, the International Space Station is in low earth orbit at an altitude of about 400km, much less than RE = 6370km .) Ignore the kinetic energy that the spacecraft has on the ground due to the earth’s rotation.
(b) Calculate the minimum amount of additional work required to move the space craft from low earth orbit to a very great distance from the earth. Ignore the gravitational effects of the sun, the moon, and the other planets.
(c) Justify the statement "In terms of energy, low earth orbit is halfway to the edge of the universe.

Physics
1 answer:
notsponge [240]3 years ago
8 0

Answer:

(a) The Work need to   place spacecraft into low orbit isGmm_{E} /2R_{E}

(b) Additional Work need to  place the spacecraft far away from the earth is

Gmm_{E} /2R_{E}.

(c) From part(a) and part(b) we observe the Both quantities are equal.

Explanation:

Explanation is in the following attachments

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Leviafan [203]

The wavelength is 2m.

Hence, Option c) 2m is the correct answer

Given that;

Frequency; f = 30Hz

Speed; v = 60m/s

Wavelength; \lambda =\ ?

using the expression for the relations between wavelength, frequency and speed of wave:

\lambda = \frac{v}{f}

Where \lambda is wavelength, f is frequency and v is speed.

We substitute our given values into the equation

\lambda = \frac{60m/s}{30Hz}\\\\\lambda = \frac{60m/s}{30s^{-1}}\\\\\lambda = 2m

The wavelength is 2m.

Hence, Option c) 2m is the correct answer.

To learn more about wavelength, click here: brainly.com/question/1347107

4 0
2 years ago
A 35kg cannonball sits at rest on a flat level surface. What is the normal force exerted on the cannon ball. Use -9.8 m/s2 for a
Tom [10]

Answer:

a) N = 343 [N]

Explanation:

We must remember Newton's third law, which tells us that the force acting on a body is equal to the normal reaction force of equal magnitude but acting in the opposite direction.

N=m*g

where:

m = mass = 35 [kg]

g = gravity acceleration = 9.81 [m/s²]

N = 35*9.8\\N= 343 [N]

8 0
3 years ago
2. If Chantal needs to travel an additional 150 meters beyond Taylor's house, but she
nirvana33 [79]
Awnser: 600 meters per hour
Step by step explication:
Covert 14 minutes to a fraction of an hour by dividing it by 60, because 60 is how many minutes in an hour and we need to convert it to a decimals. Then divide the distance, 150 meters by the fraction of an hour, .25 to abstain the velocity (speed) of 600 meters per hour.
4 0
3 years ago
Help it multiple-choice 16 and 17 only
lilavasa [31]

Answer:

16. c

17. d

Explanation:

16. Newton’s third law states that a force will always have an opposite but equal force as a reaction, so every force comes as a pair of action-reaction forces. For example, if you push on a book, the book also pushes on you.

17. If 1cm represents 15N, then 5cm must represent 15N*5=75N.

3 0
2 years ago
laser light sent through a double slit produces an interference pattern on a screen 3.0 m from the slits. If the eighth order ma
Xelga [282]

Solution :

Given the laser light which is sent through the double slit produces an interference pattern on the screen placed 3  meters from the slits.

The 8th order maximum occurs at angle = 12

So,

$8^{th} \text{ order maxima} = d \sin \theta = m \lambda$      , m = 8

$d = \frac{8 \lambda}{\sin 12}$

$\frac{\lambda}{d}= \frac{\sin 12}{8}$

$3^{rd} \text{ order maxima}= d \sin \theta_2 = m_2 \lambda$

$\sin \theta_2 = \frac{m_2 \lambda}{d}=\frac{3 \lambda}{d}$ $=0.75\ {\sin 12}$

$\theta_2 = \sin^{-1}\left(0.75\ \sin 12\right)$

   $ = \sin^{-1}\left(0.155)$

   $=8.91^\circ$

8 0
3 years ago
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