Answer:
(a) 
(b) 
(c) 
Explanation:
For a reaction involving sodium hydroxide and hydrochloric acid, the balanced equation of reaction is:
For a reaction involving sodium hydroxide and acetic acid, the balanced equation of reaction is:
For a reaction involving sodium hydroxide and phosphoric acid, the balanced equation of reaction is:
Answer:
[OH-] for this solution is 4.255*10^-12
Explanation:
We are given
[H+] = 2.35 × 10-3 M
we need to find the concentration of [OH-]
we know from Equilibrium
[H+][OH-] = 10^-14
[OH-] = 10^14/2.35*10^10^-3
[OH-] = 0.4255*10^-11
[OH] = 4.255*10^-12
Therefore the Concentration of [OH-] for this solution is 4.255*10^-12
Answer:
a) 24.7 mol
b) 790 g
Explanation:
Step 1: Given data
- Volume of the chamber (V): 200. L
- Room temperature (T): 23 °C
- Pressure of the gas (P): 3.00 atm
Step 2: Convert "T" to Kelvin
We will use the following expression.
K = °C + 273.15
K = 23°C + 273.15 = 296 K
Step 3: Calculate the moles (n) of oxygen
We will use the ideal gas equation.
P × V = n × R × T
n = P × V/R × T
n = 3.00 atm × 200. L/(0.0821 atm.L/mol.K) × 296 K = 24.7 mol
Step 4: Calculate the mass (m) corresponding to 24.7 moles of oxygen
The molar mass (M) of oxygen ga sis 32.00 g/mol. We will calculate the mass of oxygen using the following expression.
m = n × M
m = 24.7 mol × 32.00 g/mol = 790 g
The controlled variable is what he eats, the dependent variable is his weight.
a word of advice for your next ask, try to use better grammar and punctuation because this was kinda hard to follow.
Answer: A. CaO
Took the test already.
