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maria [59]
3 years ago
11

A group of big city tenants were upset about rising rent for their apartments, and decided to play a prank on the Building Manag

er. They went up to the top floor of the
building, which was 176.4 m above the sidewalk, and waited. They wanted to drop the balloon at just the right time, so they needed to make a quick calculation. How many
seconds before the Building Manager walks to the spot should they drop the balloon?
Physics
1 answer:
Naya [18.7K]3 years ago
5 0

Answer:

  t = 6 s

Explanation:

This is a free fall exercise

          y = y₀ + v₀ t - ½ g t²

If the balloon is released its initial velocity is zero, when it reaches the floor its height is also zero, we substitute

         0 = y₀ + 0  - ½ g t2

         t = √(2yo / g)

let's calculate

         t = √ (2 176.4 / 9.8)

         t = 6 s

the balloon must be released 6 s before the person reaches the building

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part a

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part b

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Answer: Electric Field between the plates E = 5.764 KV / m

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Work done by electric field

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Potential Energy of an electron gained:

E_p = m_e * g * d / (1.602*10^-19)

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Answer: Kinetic Energy of an electron gained E_k = 490 eV

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3 years ago
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