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maria [59]
3 years ago
11

A group of big city tenants were upset about rising rent for their apartments, and decided to play a prank on the Building Manag

er. They went up to the top floor of the
building, which was 176.4 m above the sidewalk, and waited. They wanted to drop the balloon at just the right time, so they needed to make a quick calculation. How many
seconds before the Building Manager walks to the spot should they drop the balloon?
Physics
1 answer:
Naya [18.7K]3 years ago
5 0

Answer:

  t = 6 s

Explanation:

This is a free fall exercise

          y = y₀ + v₀ t - ½ g t²

If the balloon is released its initial velocity is zero, when it reaches the floor its height is also zero, we substitute

         0 = y₀ + 0  - ½ g t2

         t = √(2yo / g)

let's calculate

         t = √ (2 176.4 / 9.8)

         t = 6 s

the balloon must be released 6 s before the person reaches the building

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2. A student drives 7.8-km trip to school and averages a speed of
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Answer:

<em>The total time is: t=451.22 sec</em>

<em>The average speed is: V=34.57 m/s</em>

Explanation:

<u>Average speed</u>

The average speed is calculated by dividing the total distance traveled by an object (x) by the total time it took it to travel that distance (t).

\displaystyle V=\frac{x}{t}

Since the student makes the trip in two parts, we have to calculate the total distance and the total time.

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\displaystyle t2=\frac{x2}{v2}=\frac{7,800}{36.8}=211.96\ sec

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t=239.26\ sec+211.96\ sec=451.22\ sec

\boxed{t=451.22\ sec}

The average speed is:

\displaystyle V=\frac{15,600}{451.22}=34.57\ m/s

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Answer:

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