Answer:s=0.68 m
Explanation:
Given
Inclination 
Speed of block(u)=1.6 m/s
Coefficient of kinetic Friction 
deceleration provided by friction=g\sin \theta -\mu _kg\cos \theta [/tex]
Using 
Final velocity v=0


s=0.68 m
Answer:
a little
Explanation:
First of all, it's not how you spell "tyres", it is tires.
Second of all, you already know the Mass so what you need to find out now is contact the road. You Know that your number and letter are squared so that would turn into 6m x 2.4. Then you do the math do continue on to finish it. Have a great day!! Good luck with the answer!!
Force = (mass) x (acceleration) (Newton's second law of motion)
Divide both sides of the equation by 'acceleration', and you have
Mass = (force) / (acceleration)
Mass = 17 newtons / 3.75 meters per second-sqrd = 4.533 kilograms (rounded)
Answer:
Y component = 32.37
Explanation:
Given:
Angle of projection of the rocket is, 
Initial velocity of the rocket is, 
A vector at an angle
with the horizontal can be resolved into mutually perpendicular components; one along the horizontal direction and the other along the vertical direction.
If a vector 'A' makes angle
with the horizontal, then the horizontal and vertical components are given as:

Here, as the velocity is a vector quantity and makes an angle of 33.6 with the horizontal, its Y component is given as:

Plug in the given values and solve for
. This gives,

Therefore, the Y component of initial velocity is 32.37.