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2 years ago

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A group of big city tenants were upset about rising rent for their apartments, and decided to play a prank on the Building Manag

er. They went up to the top floor of the
building, which was 176.4 m above the sidewalk, and waited. They wanted to drop the balloon at just the right time, so they needed to make a quick calculation. How many
seconds before the Building Manager walks to the spot should they drop the balloon?

1 answer:

Naya [18.7K]2 years ago

5 0

Answer:

t = 6 s

Explanation:

This is a free fall exercise

y = y₀ + v₀ t - ½ g t²

If the balloon is released its initial velocity is zero, when it reaches the floor its height is also zero, we substitute

0 = y₀ + 0 - ½ g t2

t = √(2yo / g)

let's calculate

t = √ (2 176.4 / 9.8)

t = 6 s

the balloon must be released 6 s before the person reaches the building

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