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Elan Coil [88]
4 years ago
14

What does the slope of a distance-versus time graph show you about the motion of an object

Physics
1 answer:
Katarina [22]4 years ago
7 0
Uniform velocity is the area of time vs distance graph
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What type of speed looks at a particular point in time?
bearhunter [10]
The answer is D because instantaneous means at a particular point in time
4 0
3 years ago
Strong solar winds blew dust and gas out of the solar system during which phase of the development of the Sun?
ipn [44]
The choices can be found elsewhere and as follows:

a. <span>Alpha Centauri </span>
<span>c. </span><span>T-tauri </span>
<span>b. </span><span>The Big Bang </span>
<span>d. </span><span>Nebular
</span>
I believe the correct answer from the choices listed above is option D. <span>Strong solar winds blew dust and gas out of the solar system during Nebular phase. This seems to be the most logical option from the choices. Hope this helps. Have a nice day.</span>
8 0
3 years ago
Read 2 more answers
Grasses, shrubs and trees are called producers because they make ______a. water_____b. carbon dioxide_____c. minerals_____d. foo
LekaFEV [45]
B?
Carbon Dioxid? Or is is c?














4 0
3 years ago
Read 2 more answers
A mass m attached to a spring of constant k is oscillating on a frictionless surface. A second mass of mass m is dropped on top
elixir [45]

Answer:

E. The period of oscillation increases.

Explanation:

The period of oscillation is:

T = 2π√(m/k)

Frequency is the inverse of period (f = 1/T), so as period increases, frequency decreases.

Increasing the mass will increase the period and decrease the frequency.

8 0
3 years ago
The series in the He spectrum that corresponds to the set of transitions where the electron falls from a higher level to the nf
Galina-37 [17]
Ok so here is the thing. It is necessary to introduce the atomic number Z into the following equation and the reason for that is that we are not working here with hydrogen (H). It will go like this:  
<span>E=(2.18×10^-18 J)(Z^2 )|1/(ni^2 )-1/(nf^2 )| </span>
<span>E=(2.18×10^-18 J)(2^2 )|1/(6 ^2 )-1/(4 ^2 )|=3.02798×10^-19 J </span>

<span>After that we need to plug the E value calculated into the equation. Remember that the wavelength is always positive:</span>

<span>E=hc/λ 3.02798×10^-19 J=hc/λ λ=6.56×10^-7 m </span>

so 6.56×10^-7 m or better written 656 nm is in the visible spectrum
7 0
3 years ago
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