3LiOH+Fe(NO3)3--›Fe(OH)3↓+3LiNO3
n(LiOH)=m/M=(25g)/(24g/mol)=1,0417mol
n(Fe(OH)3)=1/3n(LiOH)=0,3472mol
m(Fe(OH)3)=n*M=0,3472mol*107g/mol=37,15g
Answer:
This is a feverish body temperature.
Explanation:
hope it is okay.
Answer: Atomic number
Explanation: Atomic numbers never change, they stay the same which is why they are what elements are identified by