1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Greeley [361]
3 years ago
6

Cuál será la masa molar de una sustancia donde 7 g equivalen a 0,25 mol

Chemistry
1 answer:
Rasek [7]3 years ago
7 0
Sorry I have no idea
You might be interested in
If a snail crawls at 0.013 m/s north, how far will it travel in 60 seconds? Find time.
inessss [21]
It will have traveled 0.78 m. You find this by multiplying .013 by 60
8 0
3 years ago
Read 2 more answers
5.2 X 1026 molecules of CH4
olya-2409 [2.1K]

<h3 /><h3><u>Answer</u><u> </u><u>above</u><u> </u></h3>

<u>I</u><u> </u><u>cant</u><u> </u><u>send</u><u> </u><u>this</u><u> </u><u>with</u><u> </u><u>no</u><u> </u><u>text</u><u> </u>

<u>Have</u><u> </u><u>a</u><u> </u><u>nice</u><u> </u><u>day</u>

8 0
2 years ago
NEED HELP FAST
Blababa [14]

Answer: 1. Ethylene is a stable molecule with two carbon atoms connected by a double bond. Polyethylene is made by the reaction of multiple ethylene molecules in the presence of a catalyst.

2. The term “plastics” includes materials composed of various elements such as carbon, hydrogen, oxygen, nitrogen, chlorine, and sulfur.

3. Polyethylene (PE) is made by the reaction of multiple ethylene molecules in the presence of catalysts to break the double bond and connect the carbon atoms into a chain . The longer the chain, the higher the molecular weight. Polymers can have molecular weights in the millions.

Explanation:

6 0
2 years ago
An analytical chemist has determined by measurements that there are 96.5 moles of carbon in a sample of acetic acid. how many mo
Nadya [2.5K]
The formula of acetic acid is CH3COOH => C2H4O2.

So, the acetic acid has the same number of atoms of carbon (C) than of oxygen (O).

Therefore, the sample that contains 96.5 moles of carbon, will contain also 96.5 moles of O.

Answer: 96.5 moles of oxygen.
3 0
2 years ago
a student reacted 40 drops of an unknown amine with 20 drops of iodomethane in 2 ml of a suitable solvent mixture. after 15 minu
lutik1710 [3]

The compound formed is the quaternary ammonium salt N,N,N-trimethyl-1-phenylmethanaminium iodide.

Quaternary ammonium salts are formed when methyl iodide reacts with an amine. The quaternary ammonium salt is an ionic substance which often has a high melting point. Remember that the melting point of a substance can be used to identify the substance.

In this case, a student reacted 40 drops of an unknown amine with 20 drops of iodomethane in 2 ml of a suitable solvent mixture. after 15 minutes of reaction, a white precipitate formed. the precipitate was isolated and its melting point was recorded to be 178 °c. This precipitate must be N,N,N-trimethyl-1-phenylmethanaminium iodide (Benzyltrimethylammonium iodide) because it is a quaternary ammonium salt whose melting point is 178 °c.

Learn more: brainly.com/question/5325004

8 0
2 years ago
Other questions:
  • Oxygen is composed of only one kind of atom and can’t be separated into simpler substances. What type of matter is it? A. soluti
    9·2 answers
  • What is the original source of energy that is stored in the food that animals eat?
    11·1 answer
  • How many atoms are in 0.0246 mol K?
    11·1 answer
  • When the optically active carboxylic acid below is decarboxylated using the conditions typical in the acetoacetate synthesis, wi
    5·1 answer
  • Please Help!!
    9·1 answer
  • What element has two electrons in the outer most shell
    6·1 answer
  • Question 3
    9·1 answer
  • Can someone help me with this will mark brainliest
    15·1 answer
  • What has the lowest ionization erergy?
    5·1 answer
  • A sample of ethanol (c2h5oh) contains 4.2x10^23 hydrogen atoms. how many c2h5oh molecules are in this sample?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!