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Greeley [361]
3 years ago
6

Cuál será la masa molar de una sustancia donde 7 g equivalen a 0,25 mol

Chemistry
1 answer:
Rasek [7]3 years ago
7 0
Sorry I have no idea
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Add 3 x 10^9 +5.3 x 10^10
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</span><span>   3 x 10^9
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8 0
2 years ago
I need help on 26, 28, 36-40
gtnhenbr [62]

26. a megagram = 10⁶ grams while a kilogram = 10³ grams, so the megagram is bigger

28. a mililiter = 10⁻³ liters while a microliter = 10⁻⁶ liters, so the mililiter is bigger

36.   1 meter is equal to 100 centimeters, so the decimal moves right 2 places

37. 1 micrometer is equal to 0.001 milimeters, so the decimal moves left 3 places

38. 1 centimeter is equal to 0.00001 kilometers, so the decimal moves left 5 places

39. 1 micrometer is equal to 10⁻¹² megameters, so the decimal moves left 12 places

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5 0
3 years ago
What is the quantity of carbon-14 in a bone after 17,190 years if the initial mass of C-14 is 0.300 grams and the half-life is 5
Licemer1 [7]

Answer:

A. 0.038 g.

Explanation:

  • The decay of carbon-14 is a first order reaction.
  • The rate constant of the reaction (k) in a first order reaction = ln (2)/half-life = 0.693/(5730 year) = 1.21 x 10⁻⁴ year⁻¹.

<u><em>The integration law of a first order reaction is:</em></u>

<em>kt = ln [Ao]/[A]</em>

k is the rate constant = 1.21 x 10⁻⁴ year⁻¹.

t is the time = 17,190 years.

[Ao] is the initial concentration of carbon-14 = 0.300 g.

[A] is the remaining concentration of carbon-14 = ??? g.

∵ kt = ln [Ao]/[A]

∴ (1.21 x 10⁻⁴ year⁻¹)(17,190 years) = ln (0.300 g)/[A]

2.08 =  ln (0.300 g)/[A]

Taking exponential for both sides:

8.0 = (0.300 g)/[A]

<em>∴ [A] = 0.0375 g ≅ 0.038 g</em>

4 0
3 years ago
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