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Ad libitum [116K]
3 years ago
14

A thin metallic spherical shell of radius 41.6 cm has a total charge of 8.55 μC uniformly distributed on it. At the center of th

e shell is placed a point charge of 4.43 μC . What is the magnitude of the electric field at a distance of 17.9 cm from the center of the spherical shell?
Chemistry
1 answer:
Paul [167]3 years ago
5 0

Answer:

E = 1.2443*10⁶ N/C

Explanation:

R = 41.6 cm = 0.416 m

Q₁ = 8.55 μC = 8.55*10⁻⁶C

Q₀ = 4.43 μC = 4.43*10⁻⁶C

r = 17.9 cm = 0.179 m

K = 9*10⁹ N*m²/C²

Since r < R  we can apply Gauss's Law as follows

E = K*Q₀ / r²

⇒  E = (9*10⁹ N*m²/C²)*(4.43*10⁻⁶C) / (0.179 m)²

⇒  E = 1.2443*10⁶ N/C

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Answer:

P =  741.7 Pa

Explanation:

Pressure:

It is the force applied on object per unit area. The force is applied perpendicular to the surface.

Mathematical expression:

P = F/A

P = pressure

F = force

A = area

Given data:

Weight = 178 N

Area = 10 cm × 24 cm

Pressure = ?

Solution:

Area = 10 cm × 24 cm

Area = 240 cm²

Area = 240 /10000 = 0.024 m²

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How many liters are in a .00813M solution that contains 1.55 g of KBr?
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Answer:

                      1.602 L (or) 1602 mL

Explanation:

             Molarity is the amount of solute dissolved per unit volume of solution. It is expressed as,

                         Molarity  =  Moles / Volume of Solution    ----- (1)

Rearranging above equation for volume,

                         Volume of solution  =  Moles / Molarity    -------(2)

Data Given;

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                  Mass  =  1.55 g

First calculate Moles for given mass as,

                   Moles  =  Mass / M.mass

                   Moles  =  1.55 g / 119.002 g.mol⁻¹

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Now, putting value of Moles and Molarity in eq. 2,

                         Volume of solution  =  0.0130 mol / 0.00813 mol.L⁻¹

                         Volume of solution  = 1.60 L

or,

                         Volume of solution  =  1602 mL

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