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3 years ago

Which of the dollowing isotopes have 8 neutrons in the nucleus? 0-15 0-17 C13 O C14

Chemistry

2 answers:

aleksandr82 [10.1K]3 years ago

6 0

C14. This is because there are 6 protons and the mass number is 14. 14-6 = 8 neutrons

Lorico [155]3 years ago

4 0

Answer:

C-14 is the correct answer on edge ^ they are right

Explanation:

i can cop a like or two ?

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a) What substances are present in an aqueous buffer composed of HC2H3O2 and C2H3O2 - ?b) What happens when LiOH is added to a bu

Alex17521 [72]

Answer:

a) HC₂H₃O₂, C₂H₃O₂⁻, H₃O⁺, H₂O, OH⁻

b) HC₂H₃O₂ + LiOH ⇄ H₂O + LiC₂H₃O₂

c) C₂H₃O₂⁻ + HBr ⇄ HC₂H₃O₂ + Br⁻

Explanation:

a) In a HC₂H₃O₂/C₂H₃O₂⁻ buffer system, the following reactions take place:

HC₂H₃O₂ + H₂O ⇄ C₂H₃O₂⁻ + H₃O⁺

C₂H₃O₂⁻ + H₂O ⇄ HC₂H₃O₂ + OH⁻

Thus, the species present are: HC₂H₃O₂, C₂H₃O₂⁻, H₃O⁺, H₂O, OH⁻.

b) When LiOH is added to the buffer system, it is partially neutralized according to the following equation.

HC₂H₃O₂ + LiOH ⇄ H₂O + LiC₂H₃O₂

c) When HBr is added to the buffer system, it is partially neutralized according to the following equation.

C₂H₃O₂⁻ + HBr ⇄ HC₂H₃O₂ + Br⁻

3 0

3 years ago

Heat changes H O to steam<br> 2

Umnica [9.8K]

Yes it's True
Heat changes H2O (Water) into steam

3 0

3 years ago

Ethanol melts at -114 degree C. The enthalpy of fusion

Brut [27]

Answer: The heat required is 6.88 kJ.

Explanation:

The conversions involved in this process are :

$(1):ethanol(s)(-135^0C)\rightarrow ethanol(s)(-114^0C)\\\\(2):ethanol(s)(-114^0C)\rightarrow ethanol(l)(-114^0C)\\\\(3):ethanol(l)(-114^0C)\rightarrow ethanol(l)(-50^0C)$

Now we have to calculate the enthalpy change.

$\Delta H=[m\times c_{p,s}\times (T_{final}-T_{initial})]+n\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]+n\times \Delta H_{vap}+[m\times c_{p,g}\times (T_{final}-T_{initial})]$

where,

$\Delta H$ = enthalpy change = ?

m = mass of ethanol = 25.0 g

$c_{p,s}$ = specific heat of solid ethanol= 0.97 J/gK

$c_{p,l}$ = specific heat of liquid ethanol = 2.31 J/gK

n = number of moles of ethanol = $\frac{\text{Mass of ethanol}}{\text{Molar mass of ethanol}}=\frac{25.0g}{46g/mole}=0.543mole$

$\Delta H_{fusion}$ = enthalpy change for fusion = 5.02 KJ/mole = 5020 J/mole

$T_{final}-T_{initial}=\Delta T$ = change in temperature

The value of change in temperature always same in Kelvin and degree Celsius.

Now put all the given values in the above expression, we get

$\Delta H=[25.0 g\times 0.97J/gK\times (-114-(-135)K]+0.534mole\times 5020J/mole+[25.0g\times 2.31J/gK\times (-50-(-114))K]$

$\Delta H=6885.93J=6.88kJ$ (1 KJ = 1000 J)

Therefore, the heat required is 6.88 kJ

3 0

2 years ago

A cell is sitting in a solution containing 100 mM NaCl, and 30 mM Glucose. The inside of the cell contains 90 mM KCl and 30 mM C

kirza4 [7]

Answer

(a)

Extracellular= 0.230 osmols

Intracellular=0.270 osmols

(b)

As concentration of intracellular fluid is higher than extracellular fluid,solvent enters into the cell until the concentration inside and outside are Equal during this,the cell will become swallow.

Check attachment for calculation

7 0

3 years ago

Why is the transition state of the reaction always so high in energy? A. Breaking bonds always requires energy, and getting to t

lbvjy [14]

The answer is B. Forming bonds requires energy and breaking bonds releases energy. The transition state is the highest point in one reaction energy profile. Before the transition state, the energy increases which means transition state absorbs energy.

4 0

3 years ago

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