A square pyramid has a base side length of 8 feet. The height of each lateral face is 12 feet. What is the surface area of the p
1 answer:
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Answer:
Step-by-step explanation:
9) PQR Is an isosceles triangle
=> ∠PRQ = (180° - x)/2
PRS is an isosceles right triangle
=> ∠PRS = 45°
Have: ∠PRS + ∠PRQ = 115°
=>
=> 180 - x = (115 - 45).2 = 140
<=> x = 180 - 140 = 40
10) ABD is an isosceles right triangle => ∠ABD = 45°
BCD is an equilateral triangle => ∠CBD = 60°
have: x = ∠ABD + ∠CBD = 45° + 60° = 105°
11) have: x = y (2)
PQT is an isosceles triangle => ∠PQT = 180 - 70.2 = 40
QTS is an isosceles triangle => ∠TQS = 180 -2x
QRS is an isosceles triangle => ∠RSQ = y
have: 40 + 180 - 2x + y = 180 => 2x - y = 40 (1)
(1)(2) =>
=> x + y = 80
12) EFJ Is an equilateral triangle => ∠FJE = 60
∠FJE is the outer angle of the triangle FHJ but FHJ is an isosceles triangle
=> 60 = 2.∠JHF => ∠JHF = 30°
∠JHF is the outer angle of the triangle FHG
=> 30° = 2x
<=> x = 15°
Answer:
a) 4.392317 mt
b) 9 seconds
c)
Step-by-step explanation:
We have
where t is given in seconds and t in meters.
<em>a)How far has the point traveled 21 seconds after it started moving?</em>
By replacing t=21 in our equation we get
<em>b)If the point has traveled 3.16993 meters, how many seconds have elapsed since it started moving?</em>
We need to find a t such that f(t) =3.16993.
This can be accomplished by using the definition of
<em>c)Write a function that determines the number of seconds that have elapsed since the particle started moving in terms of the distance (in meters) the particle has traveled.</em>
is given by the definition of log