Answer:
Max shear = 8.15 x 10^7 N/m2
Explanation:
In order to find the maximum stress for a solid shaft having radius r, we will be applying the Torsion formula which can be written as;
Allowable Shear Stress = Torque x Radius / pi/2 x radius^4
Putting the values we have;
T = 2000 N/m
Radius = Diameter/2 = 0.05 / 2 = 0.025 m
Putting values in formula;
Max shear = 2000 x 0.025 / 3.14/2 x (0.025)^4
Max shear = 8.15 x 10^7 N/m2
Answer:
Explanation:
The detailed steps and appropriate calculation with analysis is as shown in the attachment.
Answer:
30.25 in Hg will be equal to 14.855 psi
Explanation:
We have given 30.25 Hg pressure
We have to convert the pressure of 30.25 Hg into psi
We know that 1 inch of Hg = 0.4911 psi
So to convert 30.25 inch Hg in psi we have to multiply with 0.4911
We have to convert 30.25 in Hg
So
So 30.25 in Hg will be equal to 14.855 psi
Answer:
676 ft
Explanation:
Minimum sight distance, d_min
d_min = 1.47 * v_max * t_total where v_max is maximum velocity in mi/h, t_total is total time
v_max is given as 50 mi/h
t_total is sum of time for right-turn and adjustment time=8.5+0.7=9.2 seconds
Substituting these figures we obtain d_min=1.47*50*9.2=676.2 ft
For practical purposes, this distance is taken as 676 ft