Answer:
Option C: water pressure.
Explanation:
Water pressure allows water to reach the top of a building.
Answer:
Information such as tolerance and scale can be found in the <u>title block</u> of an engineering drawing
Explanation:
The title block of an engineering drawing can normally be found on the lower right and corner of an engineering drawing and it carries the information that are used to specify details that are specific the drawing including, the name of the project, the name of the designer, the name of the client, the sheet number, the drawing tolerance, the scale, the issue date, and other relevant information, required to link the drawing with the actual structure or item
Answer:
A. N type impurities
B. P type impurities
Explanation:
A. The impurities contribute free electrons and changing the conducting property of the semi conductor. When a pentavalent impurities in a semi conductor( impurities with five valence electron) , the impurity atom replace some of the semi conductor atoms in the crystal structure where 4 of the valence electron would be involved in bonding of 4 neighbouring semiconductor while leaving the fifth electron to be free(negative charge carrier) which is available for detachment.
B. When a trivalence impurity is added to semiconductor, instead of excess electron, there will be excess hole created by crystals. Reason for this attribute is the trivalence atom will replace some tetra valence semiconductor atom, when three valence electrons of the 3 valence electrons of the trivalent impurity atom make bond with three neighbouring semiconductor which gives rise to lack of electron in the bond of the fourth neighbouring semiconductor which contribute a whole to the crystalline since trivalent impurity contribute excess holes to the crystal of semi conductor, this holes can accept electrons.
Explanation:
We need to rearrange the following formula for the values given in parenthesis.
(1) x+xy = y, (x)
taking x common in LHS,
x(1+y)=y
(2) x+y = xy, (x)
Subrtacting both sides by xy.
x+y-xy = xy-xy
x+y-xy = 0
x-xy=-y
x(1-y)=-y
(3) x = y+xy, (x)
Subrating both sides by xy
x-xy = y+xy-xy
x(1-y)=y
(4) E = (1/2)mv^2-(1/2)mu^2, (u)
Subtracting both sides by (1/2)mv^2
E-(1/2)mv^2 = (1/2)mv^2-(1/2)mu^2-(1/2)mv^2
E-(1/2)mv^2 =-(1/2)mu^2
So,
(5) (x^2/a^2)-(y^2/b^2) = 1, (y)
(6) ay^2 = x^3, (y)
Hence, this is the required solution.
A short framing member that fills the space between the rough sill and the soleplate is a cripple stud.
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