The molarity of the resulting solution obtained by diluting the stock solution is 3 M
<h3>Data obtained from the question </h3>
- Molarity of stock solution (M₁) = 15 M
- Volume of stock solution (V₁) = 500 mL
- Volume of diluted solution (V₂) = 2.5 L = 2.5 × 1000 = 2500 mL
- Molarity of diluted solution (M₂) =?
<h3>How to determine the molarity of diluted solution </h3>
M₁V₁ = M₂V₂
15 × 500 = M₂ × 2500
7500 = M₂ × 2500
Divide both side by 2500
M₂ = 7500 / 2500
M₂ = 3 M
Thus, the volume of the resulting solution is 3 M
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Answer:
Your answer is cells. Hope this helps!
Answer:
a) alkali metals
Explanation:
The element described above definitely belonged to the alkali metals, the first group on the periodic table. They show the properties indicated in the text.
- They are metals because only metals are lustrous and malleable. This eliminates the possibility of them being halogens and noble gases.
- Only group 1 metals reacts vigorously with water to form alkali.
- Alkali are aqueous solutions that are basic in nature.
- The reactivity of group 1 metals is due to their one extra electrons in the outer most shell.
- These electrons are easily and readily lost in order for such atoms to gain stability and replicate the nearest noble gases.
- The most reactive metal belongs to this group elements.
- This is why it is nearly impossible to find them occurring alone in free state.
- Some of the elements in this group are Li, Na, K, Rb, Cs and Fr.
- Transition metals have variable oxidation states and some can be found alone in nature.
Answer:
Empirical Formula:
The empirical formula of a compound is the simplest whole-number ratio of the numbers of the different atoms that compose the molecule of the compound. The empirical formula looks like a molecular formula.
C
2
H
2
and
C
H
are the molecular formula and the empirical formula of acetylene.
The Given Data
The mass of carbon in the compound:
m
C
=
40.6
g
The mass of hydrogen in the compound: {eq}m_H = 5.1 \ \rm...
