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irga5000 [103]
3 years ago
14

Can a helium tank ever be half empty

Chemistry
2 answers:
Ludmilka [50]3 years ago
8 0
Yes it can be I believe
maw [93]3 years ago
5 0
Technically yes, it can have half the mass it originally had
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What is the mass of 3.20x10^23 formula units of iron (III) oxide (Fe2O3)?
yaroslaw [1]

The mass of iron (III) oxide (Fe2O3) : 85.12 g

<h3>Further explanation</h3>

Given

3.20x10²³ formula units

Required

The mass

Solution

1 mole = 6.02.10²³ particles  

Can be formulated :

N = n x No

N = number of particles

n = mol

No = 6.02.10²³ = Avogadro's number

mol of Fe₂O₃ :

\tt n=\dfrac{3.2.10^{23}}{6.02.10^{23}}=0.532

mass of Fe₂O₃ (MW=160 g/mol)

\tt mass=mol\times MW=0.532\times 160=85.12~g

4 0
3 years ago
An aqueous solution contains 3.7 % NaCl by mass.
Tanya [424]

Answer:

- Molality:

m=0.65m

- Mole fraction:

x_{NaCl}=0.0116\\x_{H_2O}=0.9884

Explanation:

Hello,

- Molality: in this case, the solution is formed by 3.7% by mass of sodium chloride and water, thereby, we assume we have 100 g of solution in order to find the mass of sodium chloride as shown below:

m_{NaCl}=\frac{100g*3.7\%}{100\%} =3.7g

Hence, the moles of sodium chloride and kilograms of water are:

n_{NaCl}=\frac{3.7g}{58.45g/mol} =0.063molNaCl\\m_{H_2O}=100g-3.7g=96.3g*\frac{1kg}{1000g}=0.0963kgH_2O

With which the molality results:

m=\frac{n_{NaCl}}{m_{H_2O}}=\frac{0.063molNaCl}{0.0963kg}=0.65m

- Mole fraction: in this case, since we have previously computed the moles of sodium chloride, we now compute the moles of water as:

n_{H_2O}=\frac{96.3g}{18g/mol} =5.35molH_2O

Thus, the mole fraction of sodium chloride is:

x_{NaCl}=\frac{0.063}{5.35+0.063} =0.0116\\x_{H_2O}=\frac{5.35}{5.35+0.063} =0.9884

Best regards.

3 0
3 years ago
Read 2 more answers
The molecular mass of air, at standard pressure and temperature, is approximately 28.97 g/mol. Calculate the mass of 3.33 moles
poizon [28]
<h3>Answer:</h3>

               Mass = 96.47 g

<h3>Solution:</h3>

Data Given:

                  M.Mass  =  28.97 g.mol⁻¹

                  Moles  =  3.33 mol

                  Mass  =  ??

Formula Used:

                  Moles  =  Mass ÷ M.Mass

Solving for Mass,

                  Mass  =  Moles × M.Mass

Putting values,

                  Mass  =  3.33 mol × 28.97 g.mol⁻¹

                  Mass  =  96.4701 g

Rounding to four significant numbers,

                 Mass = 96.47 g


6 0
3 years ago
Read 2 more answers
A 500. mL gas sample is collected over water at a pressure of 740 mmHg and 25.0 °C. What is the volume of the dry gas at STP?
Lera25 [3.4K]

Answer:

Volume of dry gas at STP = 0.432 liters or 432 ml

Explanation:

Given:

Pressure (P) = 740 mmHg - 24 mmHg = 716 mmHg

Temperature (t) = 25 degrees C + 273 K = 298 K

500 ml = 0.5 l

Find:

Volume of dry gas at STP

Computation:

[P1][V1] / T1 = [P2][V2] / T2

[716][0.5] / 298 K = [760][ x Liters] / 273 K

x = 0.432 Liters

Volume of dry gas at STP = 0.432 liters or 432 ml

7 0
4 years ago
The Valence Electron shell is the first shell next to the nucleus. true or false
yawa3891 [41]
False. The closest Shell to the nucleus is called the “1 shell” valence electrons are the electrons of an atom that are located at the uppermost shell of the electron, which is called the valance shell. it has 7 electrons in its second shell which is its outer most shell and so it will have 7 valance electrons.
5 0
3 years ago
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