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scoray [572]
3 years ago
13

Is 4.565656.... Rational or Irrational

Mathematics
1 answer:
ELEN [110]3 years ago
8 0

Answer:

Rational

Step-by-step explanation:

4.5656565656... can be turned into a fraction. The number is a repeating decimal. Repeating decimals are rational numbers.

4.5656565656... = 4\frac{56}{99}

Hope this helps.

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HELP I NEED TO DO THIS NOW
Elan Coil [88]

Answer: The answer is 1:2, i hope it helps.

3 0
3 years ago
What is true for: y = 13(x - 4)2 - 4
notka56 [123]

Answer:

y=78

Step-by-step explanation:

y=13(x-4) 2-4

y=(13-52) -2

y=(-24+104)

y=78

7 0
3 years ago
Pls help with year 8 maths
agasfer [191]

Answer:

a) 1

b)11

c)4

d)1

I hope it helps you...

3 0
3 years ago
Read 2 more answers
Line s ‖ segment RP.<br><br><br><br><br><br><br> m∠1 + m∠2 + m∠3 =
3241004551 [841]

Answer:

the answer is 180 degrees.

a straight line is 180 degrees therefor m<1 + m<2+ m<3 = 180.

If I am right please mark me brainliest

Step-by-step explanation:

5 0
3 years ago
I have 100 items of product in stock. The probability mass function for the product's demand D is P(D=90)=P(D=100)=P(D=110)=1/3.
masya89 [10]

Answer:

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 96.667

The variance is 22.222

b) The probability mass function for the unfilled demand due to lack of stock is

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 3.333

The variance is 33.333

Step-by-step explanation:

If the demand is higher than 100, then you will sell 100 items only. Thus, there is a probability of 1/3+1/3 = 2/3 that you will sell 100 items, while there is a probability of 1/3 that you will sell 90.

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 1/3 * 90 + 2/3 * 100 = 290/3 = 96.667

The variance is V(X) = E(X²)-E(X)² = (1/3*90² + 2/3*100²) - (290/3)² = 200/9 = 22.222

b) If order to be unfilled demand, you need to have a demand of 110, which happens with probability 1/3. In that case, the value of the variable, lets call it Y, that counts the amount of unfilled demand due to lack of stock is 110-100 = 10. In any other case, the value of Y is 0, which would happen with probability 1-1/3 = 2/3. Thus

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 2/3 * 0 + 1/3 * 10 = 10/3 = 3.333

The variance is 2/3*0² + 1/3*10² = 100/3 = 33.333

4 0
3 years ago
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