(3.5mol)(24.106 g/1mol c6h6) =84.371 g C6H6
Chlorine. Electronegativity rises as you go up and to the right on the periodic table.
Answer:
a) 0.100 M
b) 0.395 M
Explanation:
a) Calculate the molarity of a solution that contains 0.200 moles of NaOH (solute) in 2.00 L of solution
We will use the following expression for molarity.
[NaOH] = moles of solute / liters of solution
[NaOH] = 0.200 mol/2.00 L = 0.100 M
b) Calculate the molarity for a solution that contains 15.5 g of NaCl (solute, 58.44 g/mol) in 671 mL of solution
We will use the following expression for molarity.
[NaCl] = mass of solute / molar mass of solute × liters of solution
[NaCl] = 15.5 g / 58.44 g/mol × 0.671 L = 0.395 M
the answer is the last one :All of these
Answer:
See explaination
Explanation:
The second intermediate formed in the pyruvate dehydrogenase mechanism is as shown in the attached file.