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s2008m [1.1K]
2 years ago
12

What is a better indicator in the titration of HCl with Na2CO3, methyl orange or methyl red, and why​

Chemistry
1 answer:
irina [24]2 years ago
7 0
HD tuy izle lütfen yalvarırım sana da hayırlı kandiller diliyorum
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the charge is negative

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Your blood can be tested to show your inheritance which is you DNA

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The red lionfish (shown below) is a voracious predator of small fish, including young angelfish and parrotfish. In the Caribbean
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4 0
3 years ago
Which phrase describes a characteristic of an Arrhenius base?
Tom [10]

 The phrase  that describes a   characteristic   of an Arrhenius base is  that Arrhenius  base add  hydroxide  ions  to  the solution ( answer C)

 

      <u><em>Explanation</em></u>

Arrhenius base  is a substance that  increases  the concentration  of OH-  in aqueous  solution.

The Common Arrhenius base are  group 1 and  2 hydroxide  such as LiOH, NaOH ,  Ba(OH)2  among others.  

for  example  NaOH  dissociate  as follows , NaOH  →  Na+(aq) + OH- (aq)


6 0
3 years ago
Read 2 more answers
The breaking buffer that we use this week contains 10mM Tris, pH 8.0, 150mM NaCl. The elution buffer is breaking buffer that als
olasank [31]

Answer:

A breakdown of the breaking buffer was first listed with its respective component and their corresponding value; then a table was made for the stock concentrations in which the volume that is being added was determined by using the formula M_1*V_1 = M_2*V_2. It was the addition of these volumes altogether that make up the 0.25 L (i.e 250 mL)  with water

Explanation:

Given data includes:

Tris= 10mM

pH = 8.0

NaCl = 150 mM

Imidazole = 300 mM

In order to make 0.25 L solution buffer ; i.e (250 mL); we have the following component.

Stock Concentration             Volume to be             Final Concentration

                                               added            

1 M Tris                                     2.5 mL                         10 mM

5 M NaCl                                  7.5 mL                        150 mM

1 M Imidazole                           75 mL                         300 mM    

M_1*V_1 = M_2*V_2. is the formula that is used to determine the corresponding volume that is added for each stock concentration

The stock concentration of Tris ( 1 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.01 M *250mL\\V_1 = 2.5mL

The stock concentration of NaCl (5 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.15 M *250mL\\V_1 = 7.5mL

The stock concentration of Imidazole (1 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.03 M *250mL\\V_1 = 75mL

Hence, it is the addition of all the volumes altogether that make up 0.25L (i.e 250 mL) with water.

5 0
3 years ago
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